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In a plant pathology paper I found levels of fertilisation applied in the experiment expressed as nitrogen equivalent. Reporting the exact phrase:

Nitrogen fertilisation with 8.6 g of nitrogen equivalent …

I found that equivalent weight for an element would be its atomic weight divided by its valency so, if I'm not wrong, equivalent weight for N would be ~4.67 g

What does this mean? How much fertiliser was applied e.g. using ammonium sulfate?

Jan
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kofm
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1 Answers1

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This is referring only to the mass of elemental nitrogen available, rather than the total mass of fertilizer. In your case, ammonium sulfate is 21% nitrogen (see the table here for other fertilizers and here for more information on fertilizer composition), which gives ~40.95g ammonium sulfate.

Pentaborane
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