Why does attaching an $\ce{-NO2}$ group at the ortho position of benzoic acid cause $\ce{-COOH}$ to become perpendicular to the plane of the benzene ring? Why doesn't the nitro group get pushed out while $\ce{-COOH}$ stays on the plane?
Also, in the case of two $\ce{-NO2}$ groups attached on the ortho and meta positions of benzoic acid, both the nitro groups become perpendicular to the benzene ring while $\ce{-COOH}$ remains at an angle to the plane. Why doesn't it become perpendicular this time?
Here is what I referred to for the structure of 2-nitrobenzoic acid :https://pubchem.ncbi.nlm.nih.gov/compound/2-Nitrobenzoic-acid#section=3D-Conformer&fullscreen=true
Here is what I referred to for the structure of 2,3-dinitrobenzoic acid :https://pubchem.ncbi.nlm.nih.gov/compound/2,3-diNitrobenzoic-acid#section=3D-Conformer&fullscreen=true
If you feel these structures arent correct please do give a reference to where I can find the right structure. :)