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By considering z[sqrt[-2]] show that x^2+2=y^3 only has two integer solutions, (+/-5,3)

I can see that N(x+i Sqrt[2])=y^3, I think x+i Sqrt[2] is prime in z[i Sqrt[2]] so y^(3/2) must be x+i Sqrt[2] but I don't really see how any of this helps. I think I'm missing something.

Mmm
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  • I think you could be right, thank you for finding this for me, I looked for ages. – Mmm Mar 01 '15 at 01:16
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    Also, putting here the obligatory link to the mathjax primer for how to type in $\LaTeX$ on this site for making posts much easier to read. http://meta.math.stackexchange.com/questions/5020/mathjax-basic-tutorial-and-quick-reference – JMoravitz Mar 01 '15 at 01:55

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