How to use With on previously defined expressions

Question

The command With[{x = 1}, x] outputs 1.

The command t = x; With[{x = 1}, t] outputs x.

I expected this second input to give the same answer. How can I modify my code so it behaves in this way?

To give you an idea: try t=x; With[{x=1}, {x, t}]. – J. M.'s missing motivation Nov 11 '15 at 14:05 — J. M.'s missing motivation, Nov 11 '15 at 14:05

score 5 · Answer 1 · answered Nov 11 '15 at 14:07

5

t = x; With[{x = 1}, Evaluate[t]]

answered Nov 11 '15 at 14:07

Coolwater

score 4 · Accepted Answer · answered Nov 11 '15 at 14:22

4

I think you are confusing the behaviour of With and Block

t = x; Block[{x = 1}, t]
(* 1 *)

answered Nov 11 '15 at 14:22

ybeltukov

Yes, this works better for my more complicated actual situation. Thanks :) – Tom Nov 11 '15 at 14:42

2 Answers2