How to increase row height while using booktabs?

Question

I'm making a table using booktabs. One of the columns contains a series of fractions.

\documentclass[12pt, letterpaper]{article}
    \usepackage{nag}
    \usepackage[margin=1.0in]{geometry}

    \usepackage{amsmath}

    \usepackage{booktabs}
    \usepackage[tableposition=top]{caption}

\begin{document}

\begin{table}[htbp]
\centering
\caption{Test}
\begin{tabular}{llll}
    \toprule
    A & B & C & D \\
    \midrule
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \\
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \\
    A: $\frac{7}{16}$ B: $\frac{3}{16}$ C: $\frac{3}{16}$ D: $\frac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \\
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \\
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \\
    \bottomrule
\end{tabular}
\end{table}

\end{document}

This is what is looks like:

table

The height of each row is just a tad too small -- the fractions are uncomfortably squished. Is there any way I can increase the row height so the fractions fit more comfortably?

If possible, I'd also like to avoid making any changes to other tables that I might add to my document.

Uwe Ziegenhagen · Accepted Answer · 2012-11-03T06:38:16.573

38

For single lines booktabs provides \addlinespace:

\documentclass{article}
\usepackage{booktabs}
\begin{document}
\begin{table}\centering
\begin{tabular}{lrc} 
\toprule[2pt]
a & b & c \\ 
\cmidrule[1pt](rl){1-3}
d & e & f \\ 
j & k & l \\ 
\addlinespace[0.5em]
g & h & i \\ 
\bottomrule[2pt] 
\end{tabular}\caption{abcde}
\end{table}
\end{document}

screenshot taken from Beamer document

edited Nov 03 '12 at 06:38

answered Nov 02 '12 at 05:53

Uwe Ziegenhagen

13,168
5
53
93

1

Though your output more looks like beamer (no Table number, sans serif font) and you definetly defined a german package - the addlinespace is the “right” way to do it, which is provided by booktabs – Ronny Nov 02 '12 at 08:38

score 21 · Answer 2 · edited Apr 13 '17 at 12:35

The easiest here would be to adjust the value of \arraystretch. For example,

\renewcommand{\arraystretch}{2}

Here's a view on the difference:

enter image description here

\documentclass[12pt, letterpaper]{article}
%\usepackage{amsmath}
%\usepackage{nag}
\usepackage[margin=1.0in]{geometry}% http://ctan.org/pkg/geometry
\usepackage{booktabs}% http://ctan.org/pkg/booktabs
%\usepackage[tableposition=top]{caption}

\newcommand{\mytable}{%
  \begin{tabular}{llll}
    \toprule
    A & B & C & D \\
    \midrule
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \\
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \\
    A: $\frac{7}{16}$ B: $\frac{3}{16}$ C: $\frac{3}{16}$ D: $\frac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \\
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \\
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \\
    \bottomrule
\end{tabular}
}

\begin{document}

\begin{table}
  \centering
  \caption{Test}
  \mytable
\end{table}

\begin{table}
  \centering
  \caption{Test}
  \renewcommand{\arraystretch}{2}
  \mytable
\end{table}

\end{document}

Note that this affects the entire table. For more (including individual modifications), see Column padding in tables.

I don't recommend this since \arraystretch in conjunction with booktabs breaks the symmetry as you can clearly see above! — Suuuehgi, Oct 13 '14 at 17:10

egreg · Answer 3 · 2017-03-22T08:35:14.193

This might seem complicated, but allows for fine tuning the output: since fractions are the culprits in this particular situation and changing \arraystretch would affect all table rows, I propose to use a different command for the fractions, so as to insert a strut next to them; this strut is larger than the normal one and computed from the fractions themselves.

\documentclass[12pt, letterpaper]{article}
\usepackage[margin=1.0in]{geometry}

\usepackage{amsmath}

\usepackage{booktabs}
\usepackage[tableposition=top]{caption}

\newcommand{\fracpadding}{}
\newcommand{\setfracpadding}[1][2pt]{%
  \sbox0{$\frac{1}{2}$}%
  \dimen0=\ht0 \advance\dimen0 #1\relax
  \dimen2=\dp0 \advance\dimen2 #1\relax
  \edef\fracpadding{\vrule width 0pt height \the\dimen0 depth \the\dimen2\relax}%
}
\newcommand{\afrac}[2]{\fracpadding\frac{#1}{#2}}


\begin{document}

\begin{table}[htbp]
\centering
\setfracpadding
\caption{Test}
\begin{tabular}{llll}
\toprule
A & B & C & D \\
\midrule
A: $\afrac{6}{16}$ B: $\afrac{5}{16}$ C: $\afrac{3}{16}$ D: $\afrac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \\
A: $\afrac{6}{16}$ B: $\afrac{5}{16}$ C: $\afrac{4}{16}$ D: $\afrac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \\
A: $\afrac{6}{16}$ B: $\afrac{6}{16}$ C: $\afrac{2}{16}$ D: $\afrac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \\
A: $\afrac{6}{16}$ B: $\afrac{6}{16}$ C: $\afrac{3}{16}$ D: $\afrac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \\
A: $\afrac{7}{16}$ B: $\afrac{3}{16}$ C: $\afrac{3}{16}$ D: $\afrac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \\
A: $\afrac{7}{16}$ B: $\afrac{4}{16}$ C: $\afrac{3}{16}$ D: $\afrac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \\
A: $\afrac{7}{16}$ B: $\afrac{4}{16}$ C: $\afrac{4}{16}$ D: $\afrac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \\
A: $\afrac{7}{16}$ B: $\afrac{5}{16}$ C: $\afrac{2}{16}$ D: $\afrac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \\
A: $\afrac{7}{16}$ B: $\afrac{5}{16}$ C: $\afrac{3}{16}$ D: $\afrac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \\
\bottomrule
\end{tabular}
\end{table}

\end{document}

The default padding is 2pt above and below the fraction; one can also say \setfracpadding[3pt] or with another length. Instead of setting it globally, I suggest to set it where needed; so if you change your mind and decide to typeset a table with such fractions in smaller type, you can simply add the \small or \footnotesize declaration just before \setfracpadding.

enter image description here

score 8 · Answer 4 · edited Apr 13 '17 at 12:35

I'd avoid the problem by using slightly smaller in-line fractions with \nfrac{7}{16}. See also how to define \xfrac, another macro (and package) for in-line fractions.

\documentclass[12pt, letterpaper]{article}
\usepackage[margin=1.0in]{geometry}% http://ctan.org/pkg/geometry
\usepackage{booktabs}% http://ctan.org/pkg/booktabs

\makeatletter
\def\nfrac#1#2{\check@mathfonts%
    \raise.5ex\hbox{\the\scriptfont0 #1}%
    \kern-.1em/\kern-.15em%
    \lower.25ex\hbox{\the\scriptfont0 #2}}
\makeatother

\newcommand{\mytable}{%
  \begin{tabular}{llll}
    \toprule
    A & B & C & D \\
    \midrule
    A: $\nfrac{6}{16}$ B: $\nfrac{5}{16}$ C: $\nfrac{3}{16}$ D: $\nfrac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \\
    A: $\nfrac{6}{16}$ B: $\nfrac{5}{16}$ C: $\nfrac{4}{16}$ D: $\nfrac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \\
    A: $\nfrac{6}{16}$ B: $\nfrac{6}{16}$ C: $\nfrac{2}{16}$ D: $\nfrac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \\
    A: $\nfrac{6}{16}$ B: $\nfrac{6}{16}$ C: $\nfrac{3}{16}$ D: $\nfrac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \\
    A: $\nfrac{7}{16}$ B: $\nfrac{3}{16}$ C: $\nfrac{3}{16}$ D: $\nfrac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \\
    A: $\nfrac{7}{16}$ B: $\nfrac{4}{16}$ C: $\nfrac{3}{16}$ D: $\nfrac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \\
    A: $\nfrac{7}{16}$ B: $\nfrac{4}{16}$ C: $\nfrac{4}{16}$ D: $\nfrac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \\
    A: $\nfrac{7}{16}$ B: $\nfrac{5}{16}$ C: $\nfrac{2}{16}$ D: $\nfrac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \\
    A: $\nfrac{7}{16}$ B: $\nfrac{5}{16}$ C: $\nfrac{3}{16}$ D: $\nfrac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \\
    \bottomrule
\end{tabular}
}

\begin{document}

\begin{table}
  \centering
  \caption{\strut Test}
  \mytable
\end{table}

\end{document}

$Table using \nfrac$

score 5 · Answer 5 · edited Jun 10 '20 at 12:32

This is not a robust way of doing what you want but just a rusty hack:

\documentclass[12pt, letterpaper]{article}
%\usepackage{amsmath}
%\usepackage{nag}
\usepackage[margin=1.0in]{geometry}% http://ctan.org/pkg/geometry
\usepackage{booktabs}% http://ctan.org/pkg/booktabs
%\usepackage[tableposition=top]{caption}
\newcommand{\vhtable}{\rule{0pt}{15pt}}% defines the separation and can be different if you so desire for each different row.
\begin{document}
\begin{tabular}{llll}
    \toprule
    A & B & C & D \
    \midrule
    \vhtable A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \
    \vhtable A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \
    \vhtable A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \
    \vhtable A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \
    \vhtable A: $\frac{7}{16}$ B: $\frac{3}{16}$ C: $\frac{3}{16}$ D: $\frac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \
    \vhtable A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \
    \vhtable A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \
    \vhtable A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \
    \vhtable A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \
    \bottomrule
\end{tabular}
\end{document}

enter image description here

You can change the height of the rule, that is, change 15pt to whatever you feel should be the right height separation.

this would be a bit nicer if the rule had its extent divided between height and depth. there's a bit more space than needed above the first row, and not enough after the last row. some experimentation is probably necessary, but i'd start at 10pt above and 5 below to keep the total 15 used in the example. — barbara beeton, Nov 02 '12 at 13:39
@barbarabeeton I agree. Will edit as soon as I have some time or if you can add it in, no problem. — azetina, Nov 02 '12 at 17:12

score 2 · Answer 6 · edited Mar 22 '17 at 08:34

Whereas I would advice to arraystretch as in Werners answer, you can use the following macro TabV to make vertical room around a table entry. It's handy if you don't want to increase the spacing for all lines.

In the following example only the second and 6th line got more vertical space:

\documentclass[12pt,a4paper]{article}
\usepackage{booktabs}


\newcommand*{\TabV}[1]{%
  \setlength{\fboxrule}{0pt}\fbox{\hspace*{-\fboxsep}#1\hspace*{-\fboxsep}}}

\begin{document}

\begin{tabular}{llll}
    \toprule
    A & B & C & D \\
    \midrule
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \\
    A: \TabV{$\frac{6}{16}$} B: $\frac{5}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \\
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \\
    A: $\frac{7}{16}$ B: $\frac{3}{16}$ C: $\frac{3}{16}$ D: $\frac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \\
    A: $\frac{7}{16}$ B: \TabV{$\frac{4}{16}$} C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \\
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \\
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \\
    \bottomrule
\end{tabular}

\end{document}

enter image description here

score 1 · Answer 7 · answered Sep 08 '21 at 00:08

An alternative solution with tblr environment of tabularray package: there is default rowsep=2pt in tblr environment.

\documentclass[12pt, letterpaper]{article}
\usepackage{nag}
\usepackage[margin=1.0in]{geometry}
\usepackage{amsmath}
\usepackage[tableposition=top]{caption}
\usepackage{tabularray}
\UseTblrLibrary{booktabs}
\begin{document}
\begin{table}[htbp]
\centering
\caption{Test}
\begin{tblr}{llll}
    \toprule
    A & B & C & D \
    \midrule
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.9375919592 & 1.88285606369 & 0.0547358955059 \
    A: $\frac{6}{16}$ B: $\frac{5}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.94014431443 & 1.80503653258 & 0.135107781856 \
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.87649654966 & 1.81127812446 & 0.0652184251977 \
    A: $\frac{6}{16}$ B: $\frac{6}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.87992559246 & 1.76409765557 & 0.115827936888 \
    A: $\frac{7}{16}$ B: $\frac{3}{16}$ C: $\frac{3}{16}$ D: $\frac{3}{16}$ & 1.93245604561 & 1.88024081494 & 0.0522152306624 \
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{3}{16}$ D: $\frac{2}{16}$ & 1.86806360636 & 1.84960175271 & 0.0184618536479 \
    A: $\frac{7}{16}$ B: $\frac{4}{16}$ C: $\frac{4}{16}$ D: $\frac{1}{16}$ & 1.87194209421 & 1.7717822216 & 0.100159872612 \
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{2}{16}$ D: $\frac{2}{16}$ & 1.81500630063 & 1.79617969195 & 0.0188266086843 \
    A: $\frac{7}{16}$ B: $\frac{5}{16}$ C: $\frac{3}{16}$ D: $\frac{1}{16}$ & 1.81178637864 & 1.74899922306 & 0.0627871555774 \
    \bottomrule
\end{tblr}
\end{table}
\end{document}

How to increase row height while using booktabs?

7 Answers7

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