In a table, how can I draw a horizontal line that goes only through some of the cells? I mean a line like the one in the Foo and in the Bar area of this table:
+----+-----+
|Foo |1 |2 |
| |1 |2 |
| +--+--+
| |1 |2 |
| |1 |2 |
+----+-----+
|Bar |1 |2 |
| |1 |2 |
| +--+--+
| |1 |2 |
| |1 |2 |
+----+--+--+
Instead of nested tables as xport_is_sleeping suggested, you can also use \cline{2-3} which draws a partial line starting on column 2 and ending on column 3 and use \multirow to center the words Foo and Bar on the lines if that's what you want:
\documentclass{article}
\usepackage{array,multirow}
\begin{document}
\begin{tabular}{|c|cc|}\hline
\multirow{4}{*}{Foo} & 1 & 2 \\
& 1 & 2 \\\cline{2-3}
& 1 & 2 \\
& 1 & 2 \\\hline
\multirow{4}{*}{Bar} & 1 & 2 \\
& 1 & 2 \\\cline{2-3}
& 1 & 2 \\
& 1 & 2 \\\hline
\end{tabular}
\end{document}
When making tables, you should also always use the array package which offers various additional features and improvements (most notably at the vertical and horizontal lines joins).
Foo by \includegraphics[height=4em]{image} inside the \multirow in the code above.
– Philippe Goutet
Jan 09 '11 at 20:34
\raisebox{-\tabcolsep}{\includegraphics[height=4em]{image}}, it will be vertically centered, yes.
– Philippe Goutet
Jan 09 '11 at 20:58
Here's a solution using booktabs and getting rid of of the vertical rules, which leads to a prettier result imho. Have a look at the introduction of the booktabs documentation, which offers some insights in basic table design.
The benefits of booktabs are: Much better table spacing, and \toprule, \midrule and \bottomrule, where \midrule is thinner than the other two, which looks nice.
\documentclass{article}
\usepackage{booktabs}
\begin{document}
\begin{table}\centering
\begin{tabular}{lll}
\toprule
Foo & 1 & 2 \\
& 1 & 2 \\\cmidrule{2-3}% That's the rule you're looking for.
& 1 & 2 \\
& 1 & 2 \\
\midrule
Bar & 1 & 2 \\
& 1 & 2 \\\cmidrule{2-3}% This too. The numbers designate the columns covered.
& 1 & 2 \\
& 1 & 2 \\
\bottomrule
\end{tabular}
\caption{1 and 2 in relation to Foo and Bar.}
\end{table}
\end{document}
booktabs documentation explicitly mentions compatibility with longtable and provides some hints in section 5. Have a look at that, and if you still can’t work something out, feel free to ask a new question.
– doncherry
May 31 '13 at 18:45
\cmidrule{2-3}, to have \cmidrule{2, 4 and 5} in a bigger table? ANSWER: \cmidrule{2-2}\cmidrule{4-5}
– gsamaras
Mar 05 '15 at 15:15
Nested table can solve this beautifully.
\documentclass{article}
\begin{document}
\begin{tabular}{|c|@{}c@{}|}\hline
Foo
&
\begin{tabular}{cc}
1 & 2 \\
1 & 2 \\\hline
1 & 2 \\
1 & 2 \\
\end{tabular}
\tabularnewline\hline
Bar
&
\begin{tabular}{cc}
1 & 2 \\
1 & 2 \\\hline
1 & 2 \\
1 & 2 \\
\end{tabular}
\tabularnewline\hline
\end{tabular}
\end{document}
You may also try tabularray package. With tblr environment you can use \cline command to draw a colorful partial horizontal line. Furthermore, hlines can not cross multirow cells in any case, so you can simply write \hline instead of \cline in this example:
\documentclass{article}
\usepackage{tabularray}
\usepackage{xcolor}
\begin{document}
Using \verb!\cline!:
\begin{tblr}{|c|cc|}
\hline
\SetCell[r=4]{c} Foo & 1 & 2 \
& 1 & 2 \
\cline[blue3]{2-3}
& 1 & 2 \
& 1 & 2 \
\hline
\SetCell[r=4]{c} Bar & 1 & 2 \
& 1 & 2 \
\cline[purple3]{2-3}
& 1 & 2 \
& 1 & 2 \
\hline
\end{tblr}
\bigskip
Using \verb!\hline!:
\begin{tblr}{|c|cc|}
\hline
\SetCell[r=4]{c} Foo & 1 & 2 \
& 1 & 2 \
\hline[blue3]
& 1 & 2 \
& 1 & 2 \
\hline
\SetCell[r=4]{c} Bar & 1 & 2 \
& 1 & 2 \
\hline[purple3]
& 1 & 2 \
& 1 & 2 \
\hline
\end{tblr}
\end{document}
You can do that tabular easily with {NiceTabular} of nicematrix.
\documentclass{article}
\usepackage{nicematrix}
\begin{document}
\begin{NiceTabular}{|c|cc|}
\Hline
\Block{4-1}{Foo} & 1 & 2 \
& 1 & 2 \
\Hline
& 1 & 2 \
& 1 & 2 \
\Hline
\Block{4-1}{Bar} & 1 & 2 \
& 1 & 2 \
\Hline
& 1 & 2 \
& 1 & 2 \
\Hline
\end{NiceTabular}
\end{document}
I want to add just for completion:
If you want several partial lines within one row (and possibly one for only one column), then \cline{1-1}\cline{3-5} would be the correct solution. \cline{1}\cline{3-5} does not work.
