320

What is the "best LaTeX practices" for writing absolute value symbols? Are there any packages which provide good methods?

Some options include |x| and \mid x \mid, but I'm not sure which is best...

doncherry
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jamaicanworm
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    \usepackage{amsmath}...\(\lvert x\rvert\); \mid denotes a relation symbol and is wrong for the absolute value. – egreg Jan 31 '12 at 23:45
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    Should I do $\usepackage{mathtools}...\DeclarePairedDelimiter{\vert}{\lvert}{\rvert} as per your answer to a previous question? http://tex.stackexchange.com/a/42274/9757 – jamaicanworm Jan 31 '12 at 23:47
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    It's a good possibility. It depends on how many absolute values you have in your document; for a couple I wouldn't bother. But \vert is not a good choice, as it's already defined. – egreg Jan 31 '12 at 23:50
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    Thanks! Why do people not just use the keyboard | symbol? – jamaicanworm Feb 01 '12 at 00:16
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    You can actually use |, but in some situations a certain care is needed. For instance \(|{-1}|=1\) without the braces would come out wrong, while \(\lvert-1\rvert=1\) surely gives correct output. – egreg Feb 01 '12 at 00:22
  • I was anout to say to use the physics package, but when including a \frac command, it spits out an error ;( – jjdb Apr 18 '13 at 15:17
  • Maybe this \bigg\vert Or any kind of combination of \big, \Big, \bigg, \Bigg and \vert. –  Apr 18 '13 at 12:45
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    The use of mathtools is a good idea, but use \abs for the name of the new delimiter, as in \DeclarePairedDelimiter{\abs}{\lvert}{\rvert} – Máté Wierdl Feb 25 '20 at 18:20

9 Answers9

246

I have been using the code below using \DeclarePairedDelimiter from the mathtools package.

Since I don't think I have a case where I don't want this to scale based on the parameter, I make use of Swap definition of starred and non-starred command so that the normal use will automatically scale, and the starred version won't:

enter image description here

If you want it the other way around comment out the code between \makeatother...\makeatletter.

\documentclass{article}
\usepackage{mathtools}

\DeclarePairedDelimiter\abs{\lvert}{\rvert}%
\DeclarePairedDelimiter\norm{\lVert}{\rVert}%

% Swap the definition of \abs* and \norm*, so that \abs
% and \norm resizes the size of the brackets, and the 
% starred version does not.
\makeatletter
\let\oldabs\abs
\def\abs{\@ifstar{\oldabs}{\oldabs*}}
%
\let\oldnorm\norm
\def\norm{\@ifstar{\oldnorm}{\oldnorm*}}
\makeatother

\newcommand*{\Value}{\frac{1}{2}x^2}%
\begin{document}
    \[\abs{\Value}  \quad \norm{\Value}  \qquad\text{non-starred}  \]
    \[\abs*{\Value} \quad \norm*{\Value} \qquad\text{starred}\qquad\]
\end{document}
Peter Grill
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    @egreg: Agreed. But I have not encountered that with \abs yet. BTW, I like your "always is generally wrong" :-) – Peter Grill Jan 31 '12 at 23:57
  • Thanks for the help! General point of interest: why do you use \dfrac instead of plain \frac? – jamaicanworm Feb 01 '12 at 00:08
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    @jamaicanworm: I used \dfrac in this case to make a larger fraction in inline mode. This is not normally recommended in inline mode as it breaks paragraph spacing. I will update the solution to remove that. – Peter Grill Feb 01 '12 at 00:16
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    There's a reason why it's preferable to use the *-version for the automatic resizing macro: always using \left and \right is wrong, in general. – egreg Oct 15 '12 at 17:24
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    +1, even though I have to say that this answer is not very skim-reading friendly with the huge "starred"/"non-starred" picture and the remark somewhere in the text "BTW, normal behaviour is the other way around". The question OTOH is one that makes everything in this thread very prone to being skim-read. – Christian Feb 27 '13 at 18:10
  • If I could upvote for every time I've referenced this... – jwalk Aug 26 '16 at 20:56
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    a definite advantage of using commands like \abs and \norm which no one seems to have mentioned: since the | symbol has special meaning in the makeidx context, trying to enter terminology using a bare | within \index{...} will result in (delayed) errors and a lot of hair pulling for someone not really familiar with that usage. commands like the ones shown here (or even just bare \vert, \Vert or \mid) is a lot safer and worth becoming familiar with. – barbara beeton Aug 19 '17 at 03:14
  • @barbarabeeton: Excellent point! – Peter Grill Aug 19 '17 at 23:16
  • I do not understand your comment, @egreg about *. In my practice, I almost always need the automatic size changes of these delimiters. The great thing about the mathtools versions is that it's easy to change from one version to another. In many cases, I use starred versions of environments and commands more often than unstarred ones. For example, I usually use equation* or align* in final versions of a paper or book. – Máté Wierdl Jan 08 '19 at 20:58
  • It seems that all \abs solutions here do not work with pandoc for now. Why isn't this basic math operator/function be implemented by default? – Minh Nghĩa Sep 13 '20 at 18:23
107

Note if you just use | you get mathord spacing, which is different from the spacing you'd get from paired mathopen/mathclose delimiters or from \left/\right even if \left/\right doesn't stretch the symbol. Personally I prefer the left/right spacing from mathinner here (even if @egreg says I'm generally wrong:-)

\documentclass{amsart}

\begin{document}

$  \log|x||y|b $

$  \log\left|x\right|\left|y\right|b $

$  \log\mathopen|x\mathclose|\mathopen|y\mathclose|b $

\end{document}

enter image description here

David Carlisle
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88

One can also use commath package.

\documentclass{article}

\usepackage{commath}

\begin{document}
\[ \norm{a \vec{u}} = \abs{a} \, \norm{\vec{v}} \]
\end{document}

enter image description here

Wildcat
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56

The physics LaTeX package also implements abs and norm:

\documentclass{article}

\usepackage{physics}

\begin{document}
    \[ c = \abs{-c} \]
    \[ \vu{a} = \frac{\vb{a}}{\norm{\vb{a}}} \]
\end{document}

enter image description here

32

A simple, LaTeX native way of doing this is by using the \| delimiter, with the standard \left and \right modifiers (source).

For example:

\left\| \sum_{i=1}^{n} x^2 \right\|

gives

enter image description here

pietrodn
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    Also: using the | delimiter (without the preceding backslash) inserts a single vertical bar. – pietrodn Aug 11 '17 at 12:06
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    For fun try \|+a\|, as you can see this is wrong, and thus generally users should not just use |...| or \|...\| as they may accidentally come into situations where this is wrong. I'll leave it as an exercise why this happens. Plus in your example the fences does not need to be that tall. – daleif Aug 11 '17 at 12:11
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    With \|+a\| the spacing appears to be wrong, but with \left\|+a\right\| it appears to be fine. – pietrodn Aug 11 '17 at 12:19
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    Correct because one is left and the other is right. But \left and \right should only be added when actually needed (which is actually not often). My complain to your answer is that it is not good in general, for reasons that are explained in comments to other answers in this thread. – daleif Aug 11 '17 at 12:22
9
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\[
  %begin equation
\lVert w \rVert
%end equation
\]
\end{document}  

enter image description here

alhelal
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3

For LyX users: maybe I have just overlooked how to do it correctly, but I couldn't find a way of doing this natively.

I thus used a 1x1-Matrix environment and set the kind to determinant. It might just be a hack, but it works fine in my usecase.

Mene
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  • At least in the case of Lyx 2.1.4, I find that I can simply type \lvert and \rvert into my display formula and Lyx "does the right thing." In my specific case I want absolute value bars around a fraction, so I used \bigg\lvert on the one side and \bigg\rvert on the other side. – Greg Hill Apr 17 '19 at 03:48
1

If you don't want to use any package, use \mid.

Werner
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0
\documentclass[a4paper,12pt]{article}
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{esvect,commath}
\author{Nguyễn Văn Minh Hiếu}
\begin{document}
$\overrightarrow{AB}$\\
$\abs{\vv{AB}}$\\
$\abs[1]{\vv{a}}+\abs[1]{\vv{b}}=\abs[1]{\vv{c}}$\\
\end{document}
JamesT
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