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I've been looking for this topic on the internet but I don't have enough concrete answers. Suppose we have a plane with dihedral and it has a suddenly swinging to the right (watching from the nose of the plane), so the right wing goes down. I'm trying to understand why the right wing generates more lift than the left wing when it has a sideslip. I have seen in some sites that the sideslip induces a flow from the tip to the root and this makes the right wing increase locally the angle of attack, hence the lift of this wing increases too.

But, why the right wing increases the angle of attack? I think it couldn't be possible because the sideslip flow is in a different plane respect the mainstream.

SMS von der Tann
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kuvala
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    start from here – GHB Apr 08 '16 at 11:30
  • To me this is not a duplicate. We have no question on the site explaining the principle behind anhedral/dihedral. I concede, though, that some rewording might be required. – Federico Apr 08 '16 at 11:53
  • sorry, my native language is not English, so I know I have a lot of mistakes. Anyway, I know "watching from the nose" is not very clear. What I meant is " seen in the same direction that leads the mainstream " – kuvala Apr 08 '16 at 14:13

5 Answers5

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Basically, dihedral effect is that during banking, the 'lower' wing will experience a higher angle of attack compared to the 'higher' wing, and a result, a greater lift. The resulting net force and moment reduces the banking angle, reducing stability.

Consider a wing with a dihedral angle $\Gamma$ with a forward airspeed of $u$. If the sideslip angle is $\beta$, the wind due to sideslip is $u \cdot \sin\beta$. From geometry, the normal velocity induced due to dihedral, $v_{n}$ becomes $u \cdot \sin\beta \cdot \sin\Gamma$.

Dihedral angle

Image from Stability and Control of Aerospace Vehicles

Note: The notations are different in the figure; but the principle is the same.

For our purposes, we can take the sideslip velocity ($u \cdot \sin\beta$) as $v_{y}$. Now, consider two sections from the wing - one each from the 'lower' and 'higher' sides. The induced velocity is of the same magnitude in both the sides, while the direction differs, as can be seen from the above figure.

Dihedral angle

Image from people.rit.edu

Wing section

Image from Stability and Control of Aerospace Vehicles

For small angles, $v_{y}$ is nearly equal to $u \beta$. The induced angle can be given as,

$\Delta \alpha = \frac{v_{n}}{u}$.

From the earlier relations, we have,

$\Delta \alpha_{1} = \beta \cdot \sin\Gamma$, and $\Delta \alpha_{2} = -\beta \cdot \sin\Gamma$.

Because of these induced angles, the lift on the downgoing wing increases by $\Delta L$, while of the other one decreases by $\Delta L$. The net result is that the 'lower' wing experiences an increases lift, causing a rolling moment, which causes the banking angle to reduce.

Dihedral

Image from Stability and Control of Aerospace Vehicles

aeroalias
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The explanation lies in the fact that a rolled wing creates a oblique relative wind, and that a wing with a dihedral angle seen from an oblique direction is having a larger angle of attack on the side in this direction:

Looking at wings with a dihedral angle, from the wind direction
Because of the dihedral angle, for the wind coming from an oblique direction on the right of the aircraft, the right wing shows a larger AoA. This is even more important for a larger dihedral angle.

Visual demonstration

On the image below:

  • On the left side, there is an aircraft which is horizontal, flying level, and in a relative headwind. Obviously the action of the wind will be the same on both wings, whatever the dihedral angle, and the lift vector is oriented vertically (in blue).

  • On the right side, the aircraft has been disturbed and for some reason is now rolled to the right without pilot action. Imagine the heading is still the same.

Lift on horizontal and rolled wings

The key to see what will happen is to understand the right wing now develops more lift than the left wing, the difference being proportional to the dihedral angle. As soon as this is clear, we can anticipate the roll angle will be cancelled automatically, without pilot action.

Let's look at the rolled aircraft:

  • The lift vector, which is still normal to the wing, is no more vertical. From a mathematical point of view it can be split into two components along arbitrary directions. If we choose a resolution along the vertical and horizontal axes, we see the vertical component is now smaller (therefore the aircraft starts descending) and a horizontal component appeared in the process.

  • The horizontal component pulls the aircraft to the right side. As the heading is unchanged, the aircraft is not in a turn, and no centrifugal force opposes this horizontal component of the lift, therefore the aircraft starts side-slipping and the relative wind is no more a headwind, there is some crosswind from the right side.

Angle of attack seen from the relative wind standpoint:

  • When the aircraft was flying in a headwind, the angle of attack was the same for both wings.

  • With the crosswind component, the angle of attack of the right wing is higher than the angle of attack of the left wing. The difference is small when the dihedral angle is small, and increases with its value. To make this apparent, I added wings with higher dihedral angles to the aircraft:

Looking at wings with a dihedral angle, from the wind direction

Note: The difference appears only when the wind is off axis. This means the dihedral effect on the angle of attack exists only when there is a sideslip.

Of course because the angle of attack is larger on the right, a recovery moment starts developing and counteracts the initial roll. The aircraft returns to the horizontal after some damped oscillations around the longitudinal axis.

The lateral stability is of prime importance for general and commercial aviation aircraft. The dihedral angle is the most simple mean to obtain this stability, there are others.

Stability from swept wing, due to spanwise flow

Lift is generated taking into account the airflow parallel to the chord which is accelerated. Air moved in a perpendicular direction is not accelerated and doesn't create any lift, see left image:

enter image description here

(By principle, a swept wing decreases the amount of lift created, this is compensated by other benefits that make it useful anyway).

If the swept wing receives wind from an oblique direction, like during a sideslip, the available air energy will not be lost in the same proportion for each wing (see image on the right, above).

The chord of the right wing is better oriented in the airflow coming from the right, and a larger ratio of air generates lift compared to when the airflow comes frontally. This is the contrary for the left wing. This effect also contributes to lateral stability.

Preventing spiral

The dihedral angle participates to the roll stability, along with other factors. The area where the dihedral plays a critical role is the stabilization of the spiral mode (or spiral divergence).

The spiral mode, like the Dutch roll and the phugoid, is an oscillatory mode that can either self-decay with time (stable) or constantly increase (unstable). The unstable spiral mode happens this way:

  • (1) The disturbance creates a small roll moment and sideslip to the right.
  • (2) The sideslip creates a crosswind component from the right.
  • (3) The vertical stabilizer AoA increases and creates lift to the left.

    enter image description here
  • (4) Lift creates a yaw moment and turns the nose to the right.
  • (1) The yaw moment increases the roll moment and the sideslip to the right (a new cycle has begun).

If this effect is not detected and corrected, which can easily happen in IMC when the natural horizon is not visible, the aircraft continues to sideslip and yaw, while the vertical component of the lift decreases due to the roll, creating a dangerous spiral downwards which can lead to structural damages or ground collision.

The cycle is the result of all dynamic forces in action on the aircraft, in particular the lift on each wing and the position of the center of pressure.

The use of a dihedral wings affects the forces and their relative timing, and transforms an unstable spiral mode into a stable one. This is facilitated by also using a smaller vertical stabilizer and rudder, which in turn can create an unstable Dutch roll, or a shorter cabin.


Thanks to ahmetsalih for the Learjet 3D model available at TF3DM.

mins
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  • You've got me really confused. The disturbance creates the small sideslip to the right. but The sideslip creates a crosswind component from the right. This seems backwards. If you yaw right the crosswind would be from the left side. – TomMcW Apr 08 '16 at 20:31
  • When you say sideslip to the right do you mean the tail goes to the right or the nose? – TomMcW Apr 08 '16 at 20:47
  • My brain is hurting! If the nose turns to the right wouldn't the crosswind component be from the left side? – TomMcW Apr 08 '16 at 21:11
  • Plus, I thought a roll caused an adverse yaw – TomMcW Apr 08 '16 at 21:13
  • @TomMcW: The aircraft sideslips to the right ⟹ the aircraft now moves to the right ⟹ a relative crosswind from the right ⟹ the tail creates a nose yaw to the right. For the adverse yaw, yes but is cancelled by the crosswind on the tail. I added a picture for this effect. Remember this is a mechanism without dihedral, the dihedral being the solution to the unstable spiral. – mins Apr 08 '16 at 22:48
  • Ok, still one thing I'm not straight on. (Sorry to keep picking. I've been trying to understand roll stability for a long time) Your final bullet point says The yaw moment increases the sideslip. Isn't the yaw to the right due to weathervaning, therefore decreasing the slip? It would make sense if you said " "The yaw moment increases the roll" which starts the whole chain over again. – TomMcW Apr 09 '16 at 00:50
  • Excellent answer, mins, helped me understand quite a bit better. -- What boggles my mind is how the Wrights and other early aviation pioneers managed to sort all these things out to make working aircraft without really understanding what they were facing. – FreeMan Apr 09 '16 at 13:52
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    I'm sorry to nitpick an old answer, but the phrase "The spiral mode, like the Dutch roll and the phugoid, is an oscillatory mode " sounds wrong to me. The phugoid (long period) mode and the Dutch roll both have complex eigenvalues associated with them, which imply an oscillating mode (which may converge or diverge), while the spiral divergence and roll subsidience have real eigenvalues, which do not lead to oscillation. Not to say there can't be coupling or the spiral mode may not excite others, but it is not inherently an oscillatory mode. – AEhere supports Monica Jul 04 '19 at 08:12
  • @AEhere: Yes it would be more correct to call the rolling and spiral modes exponential modes. Good comment. – mins Jul 04 '19 at 09:42
  • Glad you found it useful. Also, that's the same pdf I throw at people! Helped me a lot in uni to counterbalance the theory heavy / application scarce approach of our recommended bibliography. – AEhere supports Monica Jul 04 '19 at 09:48
  • @quietflyer: "You can't explain the cause of the sideslip just by splitting the lift vector". I don't understand what you mean, the cause of the sideslip is the horizontal component created by the roll. See this explanation of Wikipedia: "In the sideslip condition, the airplane's longitudinal axis remains parallel to the original flightpath, but the airplane no longer flies along that track. The horizontal component of lift is directed toward the low wing, drawing the airplane sideways". I didn't say anything else. – mins Nov 28 '19 at 11:28
  • My comment should better have read, "You can't explain the cause of the sideslip just by noting that the net lift vector contains a horizontal component when the aircraft is banked." After all, isn't the same true in any normal "coordinated" turn? What is the particular thing about an uncommanded bank that makes it cause a sideslip as well as (presumably) a turn? – quiet flyer Nov 28 '19 at 14:10
  • More along these lines: a steady horizontal force component acting perpendicular to the flight path creates a curvature in the flight path, not a sideslip. Example: the wires on a control-line model airplane. A flat turn, no slip. But in the case you are discussing, the net force from the wing should be perpendicular to the wingspan just like in any normal coordinated turn, unless some particular thing is acting to move the aircraft sideways through the air in a sideslip. So what is that thing? – quiet flyer Nov 28 '19 at 14:13
  • @quietflyer: "You can't explain the cause of the sideslip just by noting that the net lift vector contains a horizontal component when the aircraft is banked. After all, isn't the same true in any normal coordinated turn?". Yes in a coordinated turn there is the same horizontal lift component. However as the aircraft is now turning, this force is balanced by the centrifugal force and there is no sideslip. See also this. – mins Nov 28 '19 at 16:51
  • Re above: a) so why is the aircraft not turning in the case of the uncommanded bank, just as it is in the case of the pilot-commanded bank? Or perhaps, it IS turning in both cases? b) re "see 'this'"-- not a very helpful diagram. "Centrifugal force" is not a real force and only can be included if we use the aircraft itself as our reference frame, rather than the earth. The aircraft is not a valid inertial reference frame, while the earth is. The diagram fails to include the actual aerodynamic cause of the different forces experienced in a skip versus a skid versus a coordinated turn. – quiet flyer Nov 29 '19 at 19:57
  • The diagram fails to reveal that the key difference between a "coordinated" and an "uncoordinated" turn is that in the former case, the nose of the aircraft is pointing in the same direction as the aircraft is actually moving through the air, and in the latter case, it is not, so the airflow strikes the side of the fuselage and creates an aerodynamic sideforce. So, bearing that in mind, why is an uncommanded bank and turn inherently "uncoordinated"- inherently involves a sideways component in the airflow over the aircraft- if the same is not also true of a bank and turn commanded by the pilot? – quiet flyer Nov 29 '19 at 20:04
  • @quietflyer: "So, bearing that in mind, why is an uncommanded bank and turn inherently "uncoordinated"- inherently involves a sideways component in the airflow over the aircraft- if the same is not also true of a bank and turn commanded by the pilot?". You're using the comments as a chat, I can't follow you in that direction, this is my last answer to your questions: I think the answer is pretty clear about the relative wind, and how it compares or not to a coordinated or uncoordinated turn: The disturbance doesn't create a turn, doesn't change the heading, it just rolls the wing. – mins Nov 29 '19 at 20:16
  • Re last sentence- why? Why would the aircraft not turn, once it is banked? – quiet flyer Nov 29 '19 at 20:18
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Dihedral generates a stabilizing roll torque due to the difference in angle-of-attack experienced by the left and right wings during a sideslip.

Furthermore, it's important to note that sideslip cannot be explained simply by noting that when an aircraft is banked, the tilted lift vector contains a sideways component, or that "from the point of view of the aircraft, lift is still acting in the plane of symmetry, but gravity does not and will cause it to sideslip", as is sometimes stated. (For example, we find something close to this in Martin Simons' well-known book "Model Aircraft Aerodynamics".) Those are essentially Aristotelian concepts rather than Newtonian concepts. A continuous unbalanced sideways force component causes a turn, not a sideslip. Force causes acceleration, not steady sideways motion, and turning is a curvature in the flight path which is a form of acceleration.

Rather, sideslip is a result of not being pointed the same direction you are actually going. The reason that banking tends to cause sideslip has to do with the "curving" nature of the relative wind in a turn. Since the aircraft is rotating as well as translating, different parts of the aircraft are moving through the airmass in different directions at any given instant, which means if we map out the relative wind felt by various parts of the aircraft at any given instant, we get curved lines, not straight lines. Even if the vertical fin were perfectly streamlined to the flow at any given instant, more forward parts of the aircraft-- including the wing-- would be experiencing some sideslip. This effect is especially pronounced in aircraft with low "scale speeds"-- i.e. forward airspeed divided by fuselage length.

Yaw rotational inertia can also play a role in promoting sideslip immediately after an increase in bank angle, but this is probably a minor effect.

There is one other nuance to be pointed out that is probably a only very minor effect in most cases. Imagine an aircraft with zero dihedral flying at 10 degrees of angle-of-attack. Imagine that the aircraft abruptly rolls 90 degrees and the rolling motion is about the aircraft's lateral axis, not about the airspeed vector. The angle-of-attack will be converted to sideslip-- the aircraft will end up with 10 degrees of sideslip and no angle-of-attack. Now if we add dihedral, we'll see we end up with a roll torque. However this dynamic is probably trivial in normal roll stability dynamics which involve low rates of roll, allowing the aircraft's inherent pitch stability dynamics to maintain a constant average angle-of-attack, and allowing the aircraft's inherent "weathervane" stability to oppose sideslip, so that angle-of-attack does not end up being converted into sideslip simply by virtue of the rolling motion.

quiet flyer
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0

Coming to the aid of the -5 @rbp answer, having been there, and a few items to improve the answer, and to respond to the question "how does dihedral work", as follows:

What is missing in our exaggerated 45 degree model is an evaluation of total lift, vertical lift, and center of lift relative to center of gravity.

One of the quirks of physics is that a 45 degree angled wing still produces 70.7% vertical lift of a zero degree angled wing (relative to the earths surface). This means that both wings at 45 degrees produce 42% more vertical lift than one wing at zero degrees and one at 90 degrees.

What happens when the plane rolls? Vertical lift is lower and the plane SINKS. The aircraft now has a vertical direction component, there for a change in "relative wind".

Now, where is the roll torquing force around the center of gravity coming from? Many have correctly stated that it can not be from the lift vectors, and many have correctly stated it comes from the "slip".

Notice what effect a VERTICAL component will have on the wings. Obviously the zero degree wing will be rolled up from the relative wind (vertical component) until its angle is equal to the opposite wing, restoring the original attitude and lift condition.

The side force, created by the 90 degree wing, also adds side motion. The net motion of the plane is a slip down and to the side until the wings re-level. That's the aerodynamic part, but that's not all!

When the plane rolls, the center of vertical lift, relative to the center of gravity, moves out of alignment, creating a "yin and yang" roll torque effect which also helps right the aircraft.

Dihedral is present in many aircraft designs where cruising comfort is preferred and flight other than straight and level is uncommon.enter image description here

enter image description here

Robert DiGiovanni
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  • Note: a rolling plane will have a difference in AOA between the ascending and descending wing ("roll subsidence") as explained by @aeroalias, but the roll must stop, then reverse, to return to wings level. – Robert DiGiovanni Nov 28 '19 at 12:08
  • I'm having a little trouble fully understanding your answer. Imagine we are in a 60-degree banked turn maintaining constant altitude, and then we shove the stick or yoke forward to "unload" the wing. Is it a logical corollary of your answer that an instant sideslip would result, due to the resulting sink rate? I.e. an immediate change in the direction of the "relative wind"? Causing the yaw string (if present) to swing skyward, and the slip-skid ball to fall toward the earthward end of the glass tube? Have you ever actually tried this maneuver? I have. – quiet flyer Nov 29 '19 at 20:09
  • @quiet flyer. Resulting sideslip due to loss of lift is correct. However, the issue here is NOT starting from a banked turn, it's rolling into one with a dihedralled wing. And, even with no dihedral, the loss of VERTICAL lift will cause a plane to sink. Many answers focus on the SIDE slip, I am focusing on the DROP. Please review your comment. – Robert DiGiovanni Nov 29 '19 at 22:15
  • But are you suggesting that the "drop" causes a sideways component in the relative wind, in the aircraft's reference frame? If so, see my comment above. How is a drop due to rolling into a turn different from a drop due to shoving the stick forward while banked? Sure, rolling into a turn will typically cause some sideslip due to adverse yaw and yaw rotational inertia, but will this sideslip be any more pronounced if we allow the plane to "drop" as it rolls, than if we pull the stick aft as needed to maintain altitude? – quiet flyer Dec 03 '19 at 23:12
  • Pulling the stick "aft" to maintain altitude will eliminate the drop and increase the side force. "Shoving" the stick forward could even create negative Gs! BUT BOTH ARE PILOT INPUTS, the question seems to be about dihedral stability, correcting itself from an unplanned upset such as turbulence. Dihedral increases roll stability, starting with paper airplanes on up. I am suggesting a drop helps right the plane simply because one wing is sticking out to the side more than the other. – Robert DiGiovanni Dec 04 '19 at 03:08
  • @quiet flyer so the UPPER wing may have a LOWER angle of attack as well (it is pulling towards the side). This might be akin to the "twisting" airflow some talk about. – Robert DiGiovanni Dec 04 '19 at 03:36
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This is a very exaggerated diagram of a fuselage with dihedral wings.

When the plane is flying normally (top), both wings produce the same lift vectors.

When the airplane is disturbed in the roll axis, and one wing goes higher than the other (bottom), the vertical lift vectors are different, with the "down" wing producing more vertical lift than the "up" wing. This increased vertical lift on the down wing and decreased vertical lift on the up wing, pushes the down wing up, and helps right the airplane.

Note: everything in this diagram is schematic and is not meant to indicate any specific mathematical or physics laws or formulas.

enter image description here

rbp
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    Note that in the second image, while the vertical is smaller, the horizontal, which is now above the center of gravity, would actually contribute to more bank, and possibly even overpower... Is this the cause for overbanking tendencies in steep turns? – falstro Apr 08 '16 at 15:10
  • yes, and its a good question that should be asked separately. – rbp Apr 08 '16 at 15:11
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    There is no rolling moment if the lift intensity is the same measured perpendicularly to the surfaces. – mins Apr 08 '16 at 16:19
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    I'm not sure if your explanation is correct, as it does not include a sideslip component. As I understand it, both vectors remain the same in relation to the aircraft (thus no roll moment) unless a sideslip is involved. – TomMcW Apr 08 '16 at 19:25
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    This is an oft repeated fallacy. People think that gravity is something special and lift is only measured in relation to the ground. That is false reasoning. The lift generated perpendicular to the wings are the same therefore there is no net torque to correct the bank. If we add sideslip however the higher wing would have less lift due to lower AOA. Note that if the plane does not initially have any sideslip the higher wing will contribute a net side force that will create a sideslip - so yes, even without sideslip dihedral will self-correct because it will self-create the required sideslip. – slebetman Apr 11 '16 at 07:35
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    @slebetman: Thank you for pointing this out. Just one nitpick: Your last sentence could be misunderstood that dihedral produces sideslip. The sideslip does not require dihedral - a roll angle will do it already, regardless of dihedral. The dihedral is needed to produce rolling from sideslip. – Peter Kämpf Apr 11 '16 at 10:41