In the Hodgkin-Huxley model, ionic current $i_\mathrm{Na}$ and $i_\mathrm{K}$ are given by $$ i_\mathrm{Na}=g_\mathrm{Na}(V_\mathrm{m}-V_\mathrm{Na})\\ i_\mathrm{K}=g_\mathrm{K}(V_\mathrm{m}-V_\mathrm{K}), $$ where $V_\mathrm{Na}$ and $V_\mathrm{K}$ are the equilibrium potential, and are kept the same during the burst of action potential: $$ V_\mathrm{Na}=\frac{RT}{F}\ln\mathrm{\frac{[Na^+]_o}{[Na^+]_i}}=35~\mathrm{mV},\\ V_\mathrm{K}=\frac{RT}{F}\ln\mathrm{\frac{[K^+]_o}{[K^+]_i}}=-85~\mathrm{mV} $$ This means $\mathrm{[Na^+]_o,~[Na^+]_i,~[K^+]_o,~[K^+]_i}$ are all constants, which is really confusing. In my opinion, the inward/outward current of sodium/potassium ions should definitely change the concentrations of Na+ and K+.
Well, it makes sense that $\mathrm{[Na^+]_o}$ and $\mathrm{[K^+]_i}$ can hardly change because they are large enough compared with the lost ions into the regions with fewer ion concentrations. Then what about $\mathrm{[Na^+]_i}$ and $\mathrm{[K^+]_o}$? They are so small that even very a few ions added to them can change them a lot.
For example, $\mathrm{[K^+]_i}=90~\mathrm{mM}$ and $\mathrm{[K^+]_i}=3~\mathrm{mM}$. If the potassium current leads to a change of $\mathrm{1~mM~[K^+]}$, now $\mathrm{[K^+]_i}=89~\mathrm{mM}$ and $\mathrm{[K^+]_i}=4~\mathrm{mM}$. $\mathrm{[K^+]_i}$ changes by 1.1% which can be neglected, but $\mathrm{[K^+]_o}$ changes by 33.3%, which cannot be neglected. Also, the equilibrium potential of potassium now becomes 25*ln(4/89)=-78 mV! This really changes a lot. How can we ignore it?
Moreover, in the Quantitative Model of Gastric Smooth Muscle Cellular Activation of Corrias and Buist (Annals of Biomedical Engineering, Vol. 35, No. 9, 2007), both $V_\mathrm{Ca}$ and $\mathrm{[Ca^{2+}]_i}$ does change during the burst of action potential as follows: $$ \frac{d[\mathrm{Ca}]_i}{d t}=-\frac{I_{\mathrm{caL}}+I_{\mathrm{caT}}}{2 * F * V_c}-I_{\mathrm{CaExt}}. $$ But they also ignored the change of $\mathrm{[Na^+]_i}$ and $\mathrm{[K^+]_o}$. Hmmm, really confsuing.