Given $N=5\times10^3$ and mutation rate is $\mu=10^{-5}$ per site, find the length of a DNA sequence so that the probability of mutation occuring M, is greater or equal than 0.95.
Is there a method or a formula for this type of calculation?
Given $N=5\times10^3$ and mutation rate is $\mu=10^{-5}$ per site, find the length of a DNA sequence so that the probability of mutation occuring M, is greater or equal than 0.95.
Is there a method or a formula for this type of calculation?
The mutation rate per haplotype per site is $\mu = 10^{-5}$. Assuming diploidy and a population size of $N=5000$, the population wide mutation rate per site is $10^{-5} * 5000 * 2 = 0.1$.
$0.1$ is hence the probability that a mutation occurs a at a given site (in the whole population). For 10 sites the probability that a mutation occurs at at least one site is $1 - (1-0.1)^{10} = 0.65$.
The probability we are aiming for is 0.95. So let's write the equation
$$1 - (1-0.1)^{x} = 0.95$$
, where $x$ is the number of sites we are looking for. You just have to solve for $x$ now and round up to the larger integer.
probability of mutation, I would assume it is meantprobability of 1 or more mutations, just like the formula is suggesting if $M$ means the number of mutations. – Remi.b Feb 17 '18 at 20:48mutationdo you meanmutant alleleor do you meanmutational event(see here)? – Remi.b Feb 17 '18 at 21:13