Consider the following system and analyze its behavior.
$$\begin{array}{rl} \frac{dA}{dt} &= A \left( 2-\frac{A}{5000}-\frac{L}{100} \right)\\ \frac{dL}{dt} &= L \left(-\frac{1}{2}+\frac{A}{10000} \right)\end{array}$$
The analysis
It has $3$ equilibrium points. I know the stability of the three points but I am not sure if I interpret the meaning of them correctly according to the phase portrait. $x_1, x_2$ are saddle points and $x_3$ is stable point they are
$$\overline x_1=(0,0)$$
$$\overline x_2=(10000,0)$$
$$\overline x=(5000,100)$$
According to the phase portrait I think the behavior of the system is described as:
For every point $(A,L)$ given in the first quadrant, where $A$ is the number of aphids at time $t$ and $L$ is the number of lady-bugs at time $t$, we'll have that in the future, the maximum number of lady-bugs and aphids it's going to be $(5000,100)$ respectively. This also means that both population will never going to extinct.
Even in the case where there were just a few number (near 0) of lady-bugs, their population will grow and will be establish also.
My question
Did I miss something important in the biological description to the phase portrait?
