Context
I am a teacher, and, during a class, my student asked me to draw the molecular orbital (MO) diagram of the hydroxide anion ($\ce{HO-}$). First, I made the diagram on the left, and then, when my student pointed out that the bond order is two, I corrected it by exciting some of the electrons to the antibonding orbitals, making the diagram on the right.
Note: This is a genuine attempt at explaining MO diagrams to a high school student. Please help me explain the concept right.
I attempted to draw the molecular orbital (MO) diagram of the hydroxide anion.
I have shown the one with electron filling according to Aufbau principle and the one with a simple fix I applied to correct the bond order.
The bonding ($\sigma_1$ and $\sigma_2$) and anti-bonding ($\sigma^\ast_1$ and $\sigma^\ast_2$) orbitals have been highlighted:
Now, according to the Wikipedia article on Aufbau principle, in the ground state, electrons fill subshells of the lowest available energy first, and subsequently the subshells of higher energy are filled, which is what I have done in the left diagram, $\mathrm{BO=2}$, and I have shown an excited state, with $\mathrm{BO=1}$, on the right.
Comments
- I am fully aware, as remarked by the student and in the comments, that $\ce{H}$ is not known to form a double bond.
- There might be somethings which are wrong with the MO diagrams.
- It has been pointed out that the number of MOs is more than the number of atomic orbitals (AOs), which is supposedly incorrect.
- According to the comments, one of the bonding orbitals I have drawn is non-bonding, though I do not yet know of this.
- Some comments have suggested reading a few textbooks, which I will, but it will take some time, and I will edit the question in due time, please be patient.
Question
Several comments have pointed out that this MO diagram is incorrect. What is wrong with this MO diagram and what is the correct MO diagram?

