Is the compound optically active?

Asked Mar 07 '24 at 14:01

Active Mar 07 '24 at 14:01

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My work - The compound seems to have a plane of symmetry(POS)(The plane of the compound itself seems to be the POS) Because- all carbon atoms in the benzene ring, the - COOH, the C=C, are all SP2 which means they are all planar.

The CH3's may be oriented so that the 2 H is in the plane, 1 H above, and 1 below - meaning, they are symmetric about the plane.

So I concluded that it is optically inactive but the answer states that it is indeed optically active. Where am I wrong? Thank you in advance

edited Mar 07 '24 at 14:01

asked Mar 07 '24 at 14:01

Ninjametry

1

This compound sure would "like" to be flat, but is it able to be? – Mithoron Mar 07 '24 at 14:26
Won't the Br being large try to avoid the CH3 and so become out of plane along with the rest of the group. – porphyrin Mar 07 '24 at 15:57

Is the compound optically active?

0 Answers0