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What is the mechanism of the conversion of cyclopropane-1,2,3-triyltrimethanol to benzene in in acidic medium?

conversion of cyclopropane-1,2,3-triyltrimethanol to benzene in in acidic medium

After performing E1 thrice I was expecting 1,2,3-trimethylidenecyclopropane to form instead:

1,2,3-trimethylidenecyclopropane

I know it's highly strained, but I couldn't adopt any other pathway to reach any other product. Is the triene product not formed at all? If cyclopropane-1,2,3-trione can exist, I think even the triene product can.

This reaction is from my exercise book, couldn't find it on OrgSyn.

andselisk
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Archer
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2 Answers2

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I have not written the steps for carbocation formation, simple dehydration.enter image description here

Avyansh Katiyar
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As per my knowledge, in the second step there should be migration of Hydrogen to form a 3° carbocation and then the double bond will form between the two methanol branches.This will entirely change the product but as per rule the 1° cation has to be further stabilized by shifting of hydrogen.