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I don't know why can't I draw $\ce{[HCO3]-}$ like that:

[HCO3]-

I tried to draw it like that and checked everything. I checked formal charge and all was good. Why they draw it OH I know its also alright but whats wrong with my draw? 24e checked and formal charge checked. The upper left oxygen has 6 non bonding electrons the next one has 4 non bonding electrons. It's coordinative bond.

Hand-drawn structure for [HCO3]-

andselisk
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Razi Awad
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    I suggest to review grammar, bring formatting in order and append the relevant comments into the question. Is this structure is what you have in mind? – andselisk Nov 04 '19 at 07:19
  • there is no picture its black screen . i mean its simple question everyone can understand with the picture i drew why making life hard ? if i knew the answer and someone asked i'll just tell him simple as that – Razi Awad Nov 04 '19 at 07:21
  • It's a PNG with alpha-channel enabled. Change the background from black to another color or just enable checkerboard preview for images in your browser. – andselisk Nov 04 '19 at 07:23
  • assuming this is the picture i want is it right to draw like that ? – Razi Awad Nov 04 '19 at 07:25
  • I don't know, you tell us. I just assumed this is the Lewis structure you tried to display. – andselisk Nov 04 '19 at 07:26
  • i will add a photo of my drawing through iphone but i am sure no one will answer and i will be wasting my time but i'll try maybe one good person shows up – Razi Awad Nov 04 '19 at 07:27
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    I have not enough points for a comment, but all the downratings are for the insufficient formatting of the question, not enough information on what you want, no effort in your work. What you drew and i believe you want to draw is the conjugate base (deprotonated form of the acid) of performic acid. If not, then you may have carbonic acid in mind, if so then you drew the wrong structure. Your question is not clear to me, but you may want to try ACD ChemSketch (free) software for drawing molecules. – Andrew Kovács Nov 04 '19 at 07:29
  • Technical note: please visit this page, this page and this one on how to format your future posts better with MathJax and Markdown. For drawing chemical strictures, see Software section of our Wiki. – andselisk Nov 04 '19 at 07:33
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    Do you really suppose the strongly oxidizing hydroperoxide anion group directly bound to reducing aldehyde group would survive their marriage?? It is rather a recipe for an unstable explosive. – Poutnik Nov 04 '19 at 07:36
  • my course is general chemistry I am majoring as civil enginner so i dont know what you are talking about but in highschool i do remember OH group the thing is i dont know whats wrong with my model ? – Razi Awad Nov 04 '19 at 07:38
  • As mentioned in the Andrew's post,your structure does not belong to bicarbonate anion, but to performate ( peroxyformate ) anion, what are different compounds. – Poutnik Nov 04 '19 at 08:34

1 Answers1

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Who said you couldn’t? You absolutely can. What you have shown is performic acid $\ce{CH2O3}$ (or at least its conjugate base). Just to clarify, it is obviously different to carbonic acid $\ce{H2CO3}$.

andselisk
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Certainly not a dog
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  • i have answers that only show resonance drawings which are 2 models and didn't have my drawing – Razi Awad Nov 04 '19 at 07:36
  • Your drawing is a valid molecular structure, it just isn't the structure of bicarbonate. As pointed out above, you have drawn the structure of performate (the deprotonated form of performic acid). – PCK Nov 04 '19 at 10:01
  • @RaziAwad what you have drawn is a peroxyacid which has vastly different properties to carbonic acid (which you were trying to draw), which is not, due to them having different functional groups. – Certainly not a dog Nov 04 '19 at 12:29