Stability of radicals

Asked Jul 15 '20 at 12:52

Active Jul 15 '20 at 12:59

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I recently came across a question about the stability of radicals and this option was given as correct.

$\ce {F2C^.H}>\ce {C^.H3} $

And the solution was given that $\ce{FC^.H2}$ and $\ce{F2CH^.}$ are more stable than $\ce {C^.H3}$ but $\ce{C^.F3}$ is less stable. Can anyone explain why?
If it has got something to do with inductive effect then all three $\ce {F2C^.H},\ce{FC^.H2},\ce{C^.F3}$ should be less stable than $\ce {C^.H3} $. Right?

edited Jul 15 '20 at 12:59

asked Jul 15 '20 at 12:52

JustTolerateMe

you might also want to consider lone pair repulsion between F atoms. – Safdar Faisal Jul 15 '20 at 13:15
https://chemistry.stackexchange.com/questions/49754/what-is-the-hybridisation-of-trifluoromethyl-free-radical – Mithoron Jul 15 '20 at 15:36
1

@RahulVerma Do you have anything to back up that claim? Normal radicals are electron-deficient. – Zhe Jul 16 '20 at 17:11
@Zhe: No. I don't have. As the claim was wrong. – Rahul Verma Jul 17 '20 at 04:32

Stability of radicals

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