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Given Molecule

I think that there is a chiral centers at $C_2$ and at $C_3$ (Numbering starting such that the carbon with hydroxy attached is number 2.

Then, for $C_2$:

  1. Priority would be: OH > $C_3$ > $C_1$ > H
  2. This makes it clockwise, so R

Then, for for $C_2$:

  1. Priority would be: Cl > $C_2$ > $C_4$ > H
  2. This makes it anticlock wise, so S

Therefore, the molecule becomes 2R, 3S 3-Chloro-2-pentanol.

Is this correct?

Naitik Mundra
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    Clockwise/counterclockwise change their meaning depending on whether the H is facing towards you or away. – Ivan Neretin Oct 12 '23 at 07:06
  • @IvanNeretin I know, however here I do not have any information about the H? Do I? – Naitik Mundra Oct 12 '23 at 07:06
  • @IvanNeretin I just realised, that in $C_2$, H is actually, at the front if CH3 is at the back. Then, I would have to switch them up, and it would actually become 2S, 3S. Is this correct? – Naitik Mundra Oct 12 '23 at 07:33
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    Now that looks correct to me. – Ivan Neretin Oct 12 '23 at 07:53
  • @IvanNeretin Thanks – Naitik Mundra Oct 12 '23 at 07:54
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    @NaitikMundra A program like ChemDraw (sample page) can provide a check: draw the structure, mark them by the lasso, use the structure2name function (bottom row of the icons, the fourth counting from the right hand side). But: don't rely blindly on a computer program (which may include an [accidental] error of implementing the CIP rules, and nomenclature in general) -- continue your training to be able to apply the rules by yourself. – Buttonwood Oct 12 '23 at 09:44
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    @NaitikMundra The site's resources actually compiled reference material about chemical nomenclature, too. – Buttonwood Oct 12 '23 at 09:47
  • @Buttonwood Thanks! The answer was in front of me and I never noticed. – Naitik Mundra Oct 12 '23 at 10:16

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