Free-radical substitution does not occur in aqueous solution as free radicals react with water (from school textbook). What does the reaction between free radicals, say Br, and water produce?
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You might be referring to electrophilic addition like in the video - I am referring to radical substitution. In your first link there is such a reaction but with Cl radicals instead. Was wondering what happens when these radicals react with water. – Kenneth Sep 04 '16 at 12:31
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You're right. I deleted my unhelpful comments. – DHMO Sep 04 '16 at 12:41
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My best guess would be HBr. Br2 + Water disproportions to HBr and hypobromite. That reaction is sped up by light, so it's probably a radical reaction. – Karl Sep 04 '16 at 12:51
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see this:-http://chemistry.stackexchange.com/questions/42696/how-can-bromine-water-be-called-a-solution – Nilay Ghosh Sep 10 '16 at 10:09
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Bromine radical reacts with water
$$\ce{Br* + H2O -> HBr + *OH}$$
OH radical reacts with bromine
$$\ce{*OH + Br2 -> BrOH + Br*}$$
to give a new bromine radical, and so on, until the bromine is totally consumed.
Karl
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