Problem in Colour in Cerium (IV)Sulphate due to charge transfer

Asked Mar 03 '17 at 13:13

Active Feb 15 '23 at 23:09

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My text says that $\ce{Ce(SO4)2}$ is coloured due to charge transfer spectra. It also gives other examples such as $\ce{KMnO_4}$ and $\ce{K_2Cr_2O_7}$, to which I agree but when I read the conditions for charge transfer spectra to take place it says

+6;+7;+8 show it more
if the central metal atom is diamagnetic but still if compound is showing colour.

I see $\ce{Ce}$ in its +4 oxidation state and configuration $\ce{[Xe] 4f^1 5d^1 6s^0}$ doesn't show 1st the conditions then where am I going wrong?

edited Feb 15 '23 at 23:09

thereisnoname

asked Mar 03 '17 at 13:13

Physicsapproval

ohh! no it should have been $Ce(SO_4)_2$ ; But still it doesn't hold the first condition true why? – Physicsapproval Mar 03 '17 at 15:22
Related: http://chemistry.stackexchange.com/questions/34733/why-does-a-mixture-of-siloxene-and-ceriumiv-sulfate-luminesce – Nilay Ghosh Mar 12 '17 at 13:00
I want to know why both conditions in my text are not true simultaneously? why? – Physicsapproval Mar 13 '17 at 03:55
Cerium(IV) is not $\ce{[Xe] 4f^1 5d^1 6s^0}$. With $58-4=54$ electrons it must be $\ce{[Xe]}$ only, so diamagnetic and yet colored. – Oscar Lanzi Feb 15 '23 at 23:44

Problem in Colour in Cerium (IV)Sulphate due to charge transfer

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