In $\ce{KMnO4}$, the Oxidation state of $\ce{Mn}$ is +7, which results in an electronic configuration as $\ce{[Ar] 4s^0 3d^0}$
In $\ce{K2Cr2O7}$,the Oxidation state of $\ce{Cr}$ is +6, which results in an electronic configuration as $\ce{[Ar] 4s^0 3d^0}$
As it is clearly visible there are no $\ce{d}$ electrons in either of these compounds but still, they are coloured.
My Doubt:
If there's no $\ce{d-d}$ transition in these compounds what gives these compounds their colour?
Are there other transition element compounds whose colour is not because of $\ce{d-d}$ transition?
