Is planarity really necessary for conjugation?

Question

If we look at the $\ce{ClO4-}$ anion, the chlorine atom in it is sp³ hybridised. Hence, it has a tetrahedral structure in which conjugation shouldn't be possible, but while explaining the acidic strength of $\ce{HClO4}$, I've seen many people claim that it is very acidic because the $\ce{ClO4-}$ anion is stable due to the conjugation of charge between the four oxygen atoms.

So, all of this boils down to: Is planarity really necessary for conjugation?

Comments are not for extended discussion; this conversation has been moved to chat. — orthocresol, Mar 22 '18 at 23:46
https://chemistry.stackexchange.com/questions/48113/why-is-hclo4-the-strongest-oxyacid — Mithoron, Mar 23 '18 at 17:27

score 0 · Accepted Answer · answered Apr 19 '18 at 01:50

0

this is a rather good question several students have actually asked me about it. it is not any exeption or contradiction .i have written the explanation below

answered Apr 19 '18 at 01:50

Anurag Reddy

32
1

3

Could you type your answer out please? The content seems to be very nice. Thanks – Avyansh Katiyar Apr 19 '18 at 08:06
2

I can't read that, please type it out. I would then even consider removing my down-vote. – Martin - マーチン Apr 25 '18 at 14:28

Is planarity really necessary for conjugation?

1 Answers1