How to expand $(1 - x)^{-5}$?

Question

How can I expand $(1 - x)^{-5}$ ?

There are different approaches given, but I am not getting exactly.

Can you please name the approaches that have been mentioned? It will be easy for us then to make you understand what is necessary. — SchrodingersCat, Dec 12 '16 at 04:28
Use newton binomial theorem for negative index , you can see it at wikipedia — Atul Mishra, Dec 12 '16 at 04:30
@SchrodingersCat This one uses some formula which is different from my book's forrmula. Can you please help http://math.stackexchange.com/questions/875223/number-of-ways-distribute-12-identical-action-figures-to-5-children — Jon Garrick, Dec 12 '16 at 04:31
@Garrick exactly what help do you want? please tell me what is the thing that is actually causing the confusion? — SchrodingersCat, Dec 12 '16 at 04:36

score 3 · Accepted Answer · answered Dec 12 '16 at 04:30

3

Binomial series to expand $(1-x)^{-5}$. $$\frac{1}{(1-z)^{\beta+1}} = \sum_{k=0}^{\infty}{k+\beta \choose k}z^k.$$

answered Dec 12 '16 at 04:30

Tengu

1 Answers1