How can I show that the differential equation:
$${dx \over dt }=\sqrt x, x(0)=0$$
has infinitely many solutions.
One solution will be $x={t^2 \over 4}$
How can I show that the differential equation:
$${dx \over dt }=\sqrt x, x(0)=0$$
has infinitely many solutions.
One solution will be $x={t^2 \over 4}$
Let $k$ be a positive real number. Let $f: \mathbb{R} \to \mathbb{R}$ be given by: $f(t)=0$ if $t<k$, and $f(t)=\frac{(t-k)^{2}}{4}$ for $t>k$. Now check that: