0

F (x) is a polynomial on Z_ (p), and n is an irreducible polynomial. When a is the root of f (x), is the splitting field of f (x) on Z_ (p)?

Using Frobunius automorphism we have found that a, a ^ p, ... a ^ (p ^ (n-1)) is also the root of f (x). Since Z_ (p) is a perfect field, the splitting field of f (x) is also a separable extension. I want to show that the splitting field of f (x) is Z_ (p) (a) because a, a ^ p, ..., a ^ (p ^ (n-1) My guess is wrong or can you help me? Thank you for your hlp!

0 Answers0