Find the residue of
$$f(z)=\frac{\cot(z)\coth(z)}{z^3}$$ at $z=0$.
I tried to use the Cauchy's residue formula, but the calculation is very complex. Can it be done in a simpler way?
Find the residue of
$$f(z)=\frac{\cot(z)\coth(z)}{z^3}$$ at $z=0$.
I tried to use the Cauchy's residue formula, but the calculation is very complex. Can it be done in a simpler way?
We use the Laurent series of $\cot$ and $\coth$ around $0$. See this link .
If we take $$\coth (z)=\frac 1z+\frac z 3-\frac{z^3}{45}+o(z^4)$$ $$\cot(z)=\frac 1z-\frac z 3-\frac{z^3}{45}+o(z^4)$$
Now use these expressions to calculate $\frac{\cot z \coth z}{z^3}$, the coefficient of $z^{-1}$ is by definition the residue of that expression.