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I want to show that the following inequality holds for all $k\in\mathbb{N},k\geq 1$:

$$ \frac{1}{k}-\ln\left(\frac{k+1}{k}\right)\leq\frac{1}{k^2} $$

I already know that it is bounded. It also know that $1+x\leq e^x$ for all $x\in\mathbb{R}$. and that $e^x\leq\frac{1}{1-x}$ for all $x\in [0,1)$.

StubbornAtom
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blub
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  • $\lim\limits_{n\rightarrow\infty}\left(\frac{1}{n} - \ln\left(1+\frac{1}{n}\right) \right)=0$ and any sequence with a limit is bounded. – rtybase Jan 14 '18 at 20:46
  • I edited my question, since I know that the expression is bounded but I want to provide this specific bound. – blub Jan 14 '18 at 21:44

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