0

I was trying to understand a problem relating to the beta function. In the middle of the solution, there is this line that confuses me, as I have no idea how the infinite summation simplifies to the natural logarithm.

$$\int_0^1\sum_{n=1}^{\infty}\frac{\left(x\left(1-x\right)\right)^{\left(n-1\right)}}{2n}dx=\frac{1}{2}\int_0^1\ln\left(1-x\left(1-x\right)\right)\left(x\left(1-x\right)\right)^{-1}dx$$

Robbie
  • 371

0 Answers0