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What would the tranpose of $Y$ look like $$Y ={A}^{*} \operatorname{diag} \left( b \right) {A} $$

where $*$ is the conjugate tranpose, i.e., hermitian.

abina shr
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1 Answers1

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We have $\operatorname{diag}(b)^*=\operatorname{diag}(\overline{b})$, hence

$Y^*=A^*\operatorname{diag}(\overline{b})A^{**}=A^*\operatorname{diag}(\overline{b})A$.

Fred
  • 77,394