Can someone help me with the integral
$ \int_{0}^{1} \frac{x^2-1}{\log{x}} dx $
Tried substitution $ u = \log{x} $ but nothing came out. Thanks to helpers.
Can someone help me with the integral
$ \int_{0}^{1} \frac{x^2-1}{\log{x}} dx $
Tried substitution $ u = \log{x} $ but nothing came out. Thanks to helpers.