Why is 1 over x/y equal to y/x?
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1Because $\frac xy \times \frac yx = 1$ (ignoring the possible divisions by $0$). – lulu Sep 21 '19 at 17:20
5 Answers
It is $$\frac{1}{1}:\frac{x}{y}=\frac{1}{1}\times \frac{y}{x}=\frac{y}{x}$$
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What you want to show is that the multiplicative inverse of $x/y$ is $y/x$. Since (multiplicative) inverses are unique, this follows at once from $$\frac{x}{y} \frac{y}{x} = \frac{xy}{yx} =1.$$
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All we need to prove that the multiplicative inverse of $$\frac{1}{a} \text{ is } a$$. i.e. to prove that $$\frac{1}{1/a}=a$$ This is very simpme once you observe the multiplication $$a\times\frac{1}{a}=1$$.
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Because by definition, if $ab=1,$ and $b\ne 0,$ then we have that $a=\frac1b.$ Now since $\frac yx\cdot \frac xy=1,$ it follows that $$\frac{1}{x/y}=\frac yx.$$
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Well, the division is a derived operation:
$a : b = a\cdot b^{-1}$ where $b\ne 0$.
I.e., division by $b$ means multiplication with the inverse of $b$, where $b\cdot b^{-1}=1$.
Here as lulu said,
$(\frac{x}{y})^{-1} = \frac{y}{x}$.
So
$\frac{1}{\frac{x}{y}} = 1: \frac{x}{y} = 1\cdot (\frac{x}{y})^{-1} = 1\cdot \frac{y}{x} =\frac{y}{x}$.
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