Is the definition of $p\rightarrow q$ in logic $(\lnot p) \lor q$?
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Yes . . . and no.
In classical logic, yes, $p\to q$ is defined (sometimes) as $(\lnot p)\lor q$. However, classical logic is not the only logic in town. Sometimes other symbols are used to indicate the difference, such as $p\supset q$, but such notation is also used for the material conditional, which is what is typically meant by $p\to q$.
So it depends.
Shaun
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You've got a typo; I think you accidentally replaced the "or" symbol with an arrow. – Tanner Swett Nov 14 '19 at 00:35
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Well spotted, @TannerSwett; I've corrected it now. Thank you! – Shaun Nov 14 '19 at 00:36