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If there are n people then they can be seated in a straight line in n! ways but if they are to be seated in a circle then there are (n-1)! ways. Why is this so? Can't we just treat a circle as a line? I mean that the boundary, if straightened, of a circle is just a line? Could someone please clear this confusion? Thanks.

N. F. Taussig
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ryan1
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1 Answers1

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For example, if you want to sit 5 persons(for simplicity every person is a letter; A, B, C, D, E) in a line of chairs, you can order them in 5! ways i.e 120 different ways. So if we are thinking of a circular permutation problem we can solve it similar to a linear permutation. First, you have to choose someone to be the fixed position, and then arrange the remaining persons in a different order. Suppose that ms. A goes in the first chair. You have left 4 choices for the second chair, 3 for the third, 2 for the fourth, and 1 for the fifth. That means that if you chose one person for the first chair you have 4! ways of arranging the persons in the remaining four positions of the chairs. So the number of ways of arranging A, B, C, D, E in a circle of chairs is 1x4!=24. Note that (n-1)!=n!/n. In this case we have (5-1)!=4!=24=120/5

FV S
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