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By the Riesz representation theorem, we know that the Hilbert space $\mathcal{H}$ is isomorphic to his dual. Is the converse true ? Does the fact that a Banach space $E$ is isomorphic to his dual implies that $E$ is an Hilbert space ? If it is not the case, does anyone have an example ?

Falcon
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1 Answers1

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No. For any reflexive Banach space $X$ consider $X \oplus X^*$. Then $(X \oplus X^*)^* = X^* \oplus X$, which is of course isomorphic to $X \oplus X^*$ but not necessarily a Hilbert space.

Klaus
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