Given sequence:
$A_{1} = 0$ $A_{2} = 3$ $A_{3} = \frac{3}7$ $A_{4} = \frac{21}{13}$ $A_{5} = \frac{39}{55}$
And the recursive formula is given as $_{n+1}=\frac{3}{2_{n} + 1}$
How can one find this sequence's explicit formula?
Given sequence:
$A_{1} = 0$ $A_{2} = 3$ $A_{3} = \frac{3}7$ $A_{4} = \frac{21}{13}$ $A_{5} = \frac{39}{55}$
And the recursive formula is given as $_{n+1}=\frac{3}{2_{n} + 1}$
How can one find this sequence's explicit formula?
Hint: Solve $x = \frac{3}{2 x + 1}$. Why is this a good approach?
Alternatively, consider the subsequences of $A_n$ for odd $n$ and for even $n$ and prove that they are monotonic and bounded.
It's a Möbius transformation.
check my answer at Recursive sequence depending on the parameter for a shortcut method. A few others have also posted such approach in the past.