A sequence of numbers $a_{0}, a_{1}, \cdots, a_{n}, \cdots$ is said to be log-concave if for $1 \leq i \leq n-1, a_{i-1} a_{i+1} \leq a_{i}^{2} .$ consider the sequence $\left(\begin{array}{c}k \\ k\end{array}\right),\left(\begin{array}{c}k+1 \\ k\end{array}\right),\left(\begin{array}{c}k+2 \\ k\end{array}\right), \cdots, .$ Show that this sequence is log-concave. Also give a combinatorial proof.
I did solve the question using actual computation (That is by expansion of terms). Also I could find a combinatorial proof of a similar sequence,
namely sequence $\left(\begin{array}{l}n \\ 0\end{array}\right),\left(\begin{array}{l}n \\ 1\end{array}\right), \cdots,\left(\begin{array}{l}n \\ n\end{array}\right)$ is log-concave, by considering the pairs of subsets.
But I couldn't prove that $\left(\begin{array}{c}k \\ k\end{array}\right),\left(\begin{array}{c}k+1 \\ k\end{array}\right),\left(\begin{array}{c}k+2 \\ k\end{array}\right), \cdots, .$ is log concave by any combinatorial argument. (here $k$ is fixed). Any help is highly appreciated, thanks in advance!