The Lindemann-Weierstrass theorem leads to the result that sine and cosine are transcendental whenever their argument is algebraic (as the golden ratio is—in fact, the golden ratio is constructible), except when that argument is zero. I think that this should have relevance to your question, although I'm not sure I know what you mean by "golden angle."
ETA: Ha! I see that "golden angle" simply refers to the angle
corresponding to the division of a circle's circumference into two
parts related by the golden ratio. The shorter arc turns out, in
radians, to be simply $(4-2\phi)\pi$, I believe. Since $4-2\phi$ is
algebraic, and $\pi$ is transcendental, their product is
transcendental. Sorry, I thought you meant something like the angle
for which the sine or cosine or tangent was something related to the
golden ratio.
In degrees, this value is $720-360\phi$, so it, like $\phi$ itself,
is algebraic.
Some basic definitions:
- An algebraic number is one that is the root of a non-zero polynomial with rational (or integer) coefficients. This includes complex numbers.
- A constructible number is the length of a line segment that can be constructed with a finite sequence of compass-and-straightedge operations. That's a geometric interpretation; the algebraic interpretation is that it falls within a finite tower of quadratic extensions (which may be gobbledygook to you, conceivably), or alternatively that it is the result of combining a finite number of arithmetic operations plus square root as applied to rational (or integer) values. All constructible numbers are algebraic, but not all algebraic numbers are constructible; the latter set is a strict superset of the former. For example, as someone pointed out in the comments to the OP, $\sqrt[3]{2}$ is algebraic but not constructible. See the Wikipedia plot summary for doubling the cube.
- A transcendental number is just one that is not algebraic. This too includes complex numbers.
See this question and its associated answer for more information. It even mentions the golden ratio, I believe.