Prove that $$1+\frac{1}{2}+\frac{1}{3}+\ldots+\frac{1}{n}>\ln n$$
The base case is trivial, but I cannot show it holds for $n+1$ if it does for $n$ :/
Prove that $$1+\frac{1}{2}+\frac{1}{3}+\ldots+\frac{1}{n}>\ln n$$
The base case is trivial, but I cannot show it holds for $n+1$ if it does for $n$ :/