I don't understand why you have to use a different variable when squared the first integral? It is commonly glossed over to explain this.
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4Otherwise you couldn't write it as a double integral – Vercassivelaunos May 23 '22 at 18:18
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Thank you but why is this a legal operation? Isn't it actually an $x$ in disguise? – bananenheld May 23 '22 at 18:24
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2@bananenheld This answer might help. Btw, it is not forbidden to accept answers. Check your previous questions. – callculus42 May 23 '22 at 18:26
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thank you callculus42. I have accepted answers. – bananenheld May 23 '22 at 21:01