I am currently practising some basic time and work questions, and focusing more on doing the stuff in an intuitive way (i.e. in the simplest way possible): I am facing a doubt regarding the way I’m thinking about the question and the way the solution is provided in textbook.
So the question is,
4 men and 6 women together do the job in 8 days, and 3 men and 7 women does the same job in 10 days.How many days the same job will be done by 10 women?
My approach is :
Considering an common multiple of 10 days and 8 days given above, i choose lets say 80, so here 80 is total unit of work. so that means in first case, 4M and 6W does job in 8 days, means they do 80/8 i.e 10 unit of work per day and similarly for second case 3M and 7W in 10 days means 80/10 i.e. 8 unit of work per day. So inorder to find how many unit of work is done by M alone and W alone, i basically simulatenously solve the equation,
$$i)\ 4M+6W=10$$ (multiply by 3).
$$ii)\ 3M+7W=8$$(multiply by 4).
Here after solving the above equation simultaneously, i get work done by W per day is 1/2 units and work done by M per day = 7/4 units. This above value when substituted in first equation it satifies but for second equation i get value as 8.75 units which is not accurate right? it should be 8. Well i know the alternate solution for the above question but want to know where i m wrong in these approach, Thanks for you kind help!:)