I tried taking both sides f which doesn't gave the solution
My work
=> f(f(n))=n+1 => Taking both sides f
=> f(f(f(n))) = f(n+1)
=> f(n+1)= f(n+1)
I am stucked here
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If you substitute $n$ with $f(n)$, you get $f(f(f(n))) = f(n) + 1$. You also showed that $f(f(f(n))) = f(n+1)$. So, $f(n+1) = f(n) + 1$. Continue from here. – Aria Oct 16 '23 at 05:43