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Domain of convergence for $\sin^{-1}(x)$ was asked. I proved that its radius of convergence is $1$. I need to check its convergence at end points. Please tell me some convergence test or some way of proving its convergence at end points.

S L
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akansha
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1 Answers1

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The series expansion of $\arcsin(x)$ is given by $$\arcsin(x) = \sum_{n=0}^\infty\frac{1}{2^{2n}} \cdot \binom{2n}{n} \cdot \frac{x^{2n+1}}{2n+1} $$ You can use Stirling approximation to show that $\displaystyle \binom{ 2n}{n}\le \frac{4^n}{\sqrt{3n+1}}$ for all $n \ge 1 $ and use $p-$ series test to show convergence.

S L
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  • A comment: it's not clear to me that the notation at the end stands for simultaneous convergence (as per the comparison test) rather than (near-)equality of series. – Jonathan Y. Aug 31 '13 at 10:27