I've observed that certain real integrals yields elements not present within the integrated function itself. For instance, integrating $\frac{1}{x}$ produces $\ln$, and specific definite integrals of $\frac{1}{x^2+1}$ involve $\pi$. Then, I'm seeking a definite or indefinite integral whose result contains $e$, despite the absence of $e$ or $e^x$ in the integrated function. Could you provide such an example or why it might not be possible?
Asked
Active
Viewed 187 times
3
-
@Mariano I presume this refers to integrating over cycles in an algebraic curve or variety? – Ted Shifrin Dec 30 '23 at 01:20
-
1A famous example, Laplace integral: $$ \int_0^{\infty} \frac{\cos bx}{a^2+x^2}, \mathrm{d}x = \frac{\pi}{2a} \mathrm{e}^{-ab}, $$ where $a,b>0$. Proof can be found here. – Huanyu Shi Jan 01 '24 at 05:09
-
But in fact, trigonometric functions and exponential functions have a very profound connection. I'm not sure if this meets the OP's criteria – Huanyu Shi Jan 01 '24 at 05:22
1 Answers
4
I found this integral from this Telegram channel
for $b \in \mathbb{R}$ $$\int_0^{\infty}\cos\bigg(x \sqrt{x^2+b^2}\bigg)dx = \frac{ \sqrt{2\pi}}{4} e^{-\frac{b^2}{2}} $$
Proof :
There are many such examples in this channel it took me under a minute to find this.
pie
- 4,192
-
@MarianoSuárez-Álvarez I don't think it is possible to have $e$ without $\sin x , \sinh x$ etc – pie Dec 30 '23 at 00:56
-
@MarianoSuárez-Álvarez Well the question is not clear enough whether trig function are allowed or not. I found tons of examples of integral of trig function that have in the result of integration.. – pie Dec 30 '23 at 01:02
-
1
