How to find the $\sum\limits_{n=1}^{\infty} \frac{1}{n6^n}$
I tried to apply the method of undetermined coefficients. But I didn't understand exactly how to apply it for $\frac{1}{6^n}$
I thought that here you can somehow apply the formula for the sum of an infinitely decreasing geometric progression, but I do not know what to do with a variable coefficient $q = \frac{1}{6n}$
It seems to me that it can be somehow reduced to ln, but I have not figured out how
