long time has passed since the question was asked but i'll explain it for newest guests.
So, if we take "n" as the # of sales (n=# of sales) and "T" for total comissions; then our first equaiton is; 250n=T,
then, for instance, Matt gets a big sale and his total comissions rise to T+1000 and number of sales rise to "n+1" and new average commission becomes 400$. Therefore we have two equations.
250n=T
400(n+1)=1000+T
on first equation, if we multiply each side by minus "-", equation won't change. then;
-250n=-T
400n+400=1000+T our new equations. Then we could sum each side of equations.
So,
150n=600, then n=4
our final amount of sales is (n+1), then the number of sales that Matt has made is n+1 = 4+1 = 5
answer is 5
old : 250n = T new : 400n = T + 1000
is my setup correct?
– user1772052 Sep 16 '13 at 15:53I believe this would be the equation for sales before the big sale.
– user1772052 Sep 16 '13 at 18:45