If we pick n+1 different positive integers with every integer is less than 2n. Prove that we can always find three numbers among these n+1 numbers that one is equal to the sum of the other two numbers.
These n+1 numbers will be chosen from 1 to 2n-1 totally 2n-1 choices. I am trying to do it by using the pigeonhole principle but I don't know how to set pigeons and holes in this case. Can someone help me? Thanks