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If we pick n+1 different positive integers with every integer is less than 2n. Prove that we can always find three numbers among these n+1 numbers that one is equal to the sum of the other two numbers.

These n+1 numbers will be chosen from 1 to 2n-1 totally 2n-1 choices. I am trying to do it by using the pigeonhole principle but I don't know how to set pigeons and holes in this case. Can someone help me? Thanks

jin ha
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1 Answers1

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hint: let the largest number in the set be $k<2n$.

Apply pigeonhole principle to the pairs of numbers which add up to $k$.

Calvin Lin
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