Suppose I have n bins and n balls with label on them. What would be the probability that I throw the i th ball into the same bin as the j th ball? Is it just 1/n because there is a probability of 1/n for the i th ball to fall into the same bin as wherever the j th is.
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1yes, assuming that the probability for each bin is 1/n – ZKe Nov 11 '13 at 01:11