On long car journeys with kids we are all familiar with "I spy" or "Twenty questions". What math related games can one play on a car journey instead that are fun and offer similar variety?
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1The “What number am I?”-game. “What number am I? If you double me an add $9$ you'll get $19$.” A very advanced schizophrenic one: “What number am I? If you multiply me by myself you'll get me.” Be sure that the kids invent their own numbers. – Michael Hoppe Dec 08 '13 at 16:40
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@MichaelHoppe That sounds good (could you make it an answer?). Thank you. – marshall Dec 08 '13 at 16:50
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Learn lambda calculus with this game. – Shaun Feb 09 '18 at 01:45
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The “What number am I?”-game. “What number am I? If you double me an add 9 you'll get 19.” A very advanced schizophrenic one: “What number am I? If you multiply me by myself you'll get me.” Be sure that the kids invent their own numbers.
Michael Hoppe
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2The schizophrenic one reminds me of a question I had to solve in the first seat of a math relay competition. Instead of TNYWR, the problem was something like "Let $T$ be The Number You Will Pass Back. Pass back $T^{2}-5T+9$." – Mark S. Dec 10 '13 at 03:10
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Here's one I play by myself when walking long distances.
"Verifying" the Collatz' Conjecture.
Pick any natural number $n$ you dare. Using only mental arithmetic, try to "verify" that $n$ satisfies the Collatz' Conjecture by the time you reach your destination. That is, show that there is a $k$ such that for $f:\mathbb{N}\to\mathbb{N}$ given by $$f(m)=\cases{\frac{m}2 &: $m$ is even, \\ \\ 3m+1 &: $m$ is odd,}$$ we have $f^k(n)=1$ . . . before you get to where you're heading. (You must keep "verifying" until you hit $1$, so you can't, say, stop once you've found an $\ell$ such that $f^\ell(n)$ is a power of two).
It's quite fun actually. Local pedestrians might think I'm a bit weird, though, since I'm muttering numbers to myself so often . . .
Shaun
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Try to find the prime factorization of every integer you come across - e.g. you see a 76 gas station, so you think:
$$ 76 = 2 \cdot 38 = 2 \cdot 2 \cdot 19 = 2^2\cdot 19 $$
icurays1
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1I play that one too. It's a classic and - one could argue - a good habit :) – Shaun Mar 06 '14 at 09:11
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1I do this every time I look at a digital clock, first in base 60, then in base 10. – Simply Beautiful Art Aug 01 '16 at 23:54
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The Licence Plate Game.
Pick a (simple) key for the alphabet (like
$$ \operatorname{key}(\color{blue}{\alpha })=\cases{\color{blue}{0} &$\text{ if }\color{blue}{\alpha}\in\{\color{blue}A, \dots , \color{blue}M\}$ \\ \color{blue}{1} &$\text{ if }\color{blue}{\alpha}\in\{\color{blue}N, \dots , \color{blue}Z\}$,} $$
for example, for a letter $\color{blue}{\alpha}$), some (simple) operations (like addition, multiplication, exponentiation, etc.), then pick a licence plate. The first one to calculate correctly the biggest (possible) number with it wins the round. Repeat (for a different plate).
A trivial example: Let's say you've chosen the key above and all you have is addition. Someone gets to pick a licence plate - maybe the winner from a previous round or a coin flip - and that plate is, say, $$\color{blue}{Y}344\quad \color{blue}{PNA}. $$Then the winning number might be $\color{blue}{1}+3+4+4+\color{blue}{1}+\color{blue}{1}+\color{blue}{0}=\color{red}{14}$.
You could vary this however you like. For example, you could use the winning number from the first round as a goal for the second (so, for example, you race to get as close as possible to $\color{red}{14}$ with a different licence plate), alternating thereafter.
I haven't tried this yet. It's based on a silly word game where you make the funniest nonsense you can from the letters of a given licence plate, like "$\color{blue}{\text{P}}$andas $\color{blue}{\text{N}}$udge $\color{blue}{\text{A}}$liens" or whatever, aiming for a short story :)
