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The title says it all, how can I prove the following:

Show that if a prime number $p|a^n$ then $p|a$

Hawk
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moenad
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  • What do you already know, Euclid's Lemma, Bezout's GCD Identity, or uniqueness of prime factorizations? What have you tried and where are you stuck? – Bill Dubuque Jan 14 '14 at 20:49

2 Answers2

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Hint: $p \mid m \, n \Longrightarrow p \mid m$ or $p \mid n$ for prime $p.$

Leox
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What it means for $p$ to be prime: For any $a,b\in\mathbb{Z}$, if $p|(ab)$, then either $p|a$ or $p|b$. So what can you say if $p|a^2$? How does this help you with your problem?

Neal
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