Is there any connected topological space $X$ such that $X$ is homeomorphic to $X\times X$ ?
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See also: Homeomorphism between Space and Product, Can a space $X$ be homeomorphic to its twofold product with itself, $X \times X$?, – Martin Sleziak Nov 19 '16 at 17:19
3 Answers
Yes, if $I$ is an infinite set and $Y$ any topological space, then $X = Y^I$ is homeomorphic to $X\times X$. If $Y$ is connected, so is $X$. A related but different example is given by the $\ell^p(\mathbb{N})$ spaces.
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Yes. Take any infinite set equipped with the trivial topology. A singleton also has this property.
For a more interesting example, see: Hilbert cube.
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For each natural number $i$ let $X_i=\mathbb R$ (we could choose any other connected space instead of $\mathbb R$) and define $$ X=\prod_{i\in\mathbb N} X_i. $$ Clearly $X$ is connected -- a product of connected spaces is always connected. The fact that $X\times X\cong X$ follows from the fact that, as sets, $\mathbb N\sqcup \mathbb N$ and $\mathbb N$ have the same cardinality (by $\mathbb N\sqcup \mathbb N$ I mean the union of two disjoint copies of $\mathbb N$). In fact, any bijection between $\mathbb N\sqcup \mathbb N$ and $\mathbb N$ induces a homeomorphism between $X\times X$ and $X$ by applying the bijection to indices.
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You're right, but that's not relevant. I'm talking about $\mathbb N$ as an index set, not as a topological space. – user134824 Mar 23 '14 at 14:29