Questions tagged [pointwise-convergence]

For questions about pointwise convergence, a common mode of convergence in which a sequence of functions converges to a particular function. This tag should be used with the tag [convergence].

A sequence of functions $f_n : X \to \Bbb{R}$ is said to converge pointwise to a function $f : X \to \Bbb{R}$ if $$ \lim_{n\to \infty}f_n(x) = f(x)$$ for all $x \in X$.

That is: $$\forall x \in X \forall \epsilon > 0 \exists N \in \Bbb{N}: \forall n \ge N, |f_n(x)-f(x)| < \epsilon.$$

In general, the pointwise limit is not a well-behaved operation. For example, the pointwise limit does not necessarily preserve the continuity of a function. Furthermore, the interchange of limit and integral signs does not hold in general: there exists functions $(f_n)$ with pointwise limit $f$ so that $\int_X f \ne \lim\limits_{n\to\infty} \int_X f_n$.

f_n(x) = sin^n(x) The continuous functions $\sin^{n}(x)$ (in green) converge to a discontinuous function (in red).

Pointwise convergence is often compared with . The later is stronger than the former, in the sense that uniform convergence implies pointwise convergence, while the reverse does not hold.

However, thanks to Egorov's Theorem in measure theory, pointwise convergence is almost uniform on sets of finite measure. That is, if $(f_n)$ are measurable functions defined on a measurable space, then pointwise convergence almost everywhere on a set $A$ of finite measure implies the apparently much stronger uniform convergence on $A \setminus B$, where $B$ is a set of arbitrarily small measure.

808 questions
3
votes
3 answers

Proving this pointwise limit via definition

For $f_n(x) = \frac{nx + x^2}{n^2}$, this converges pointwise to the function $f(x) = 0$. How would I prove this formally? This is my attempt: $$|f_n(x) - f(x)| = |\frac{nx + x^2}{n^2}| \leq |\frac{nx + nx^2}{n^2}| = |\frac{x + x^2}{n}|$$ So if I…
Natash1
  • 1,379
2
votes
0 answers

Subsequence in convergence of integrals

In an article I'm currently reading, a reasoning is used that I don't understand. We have an integral of a function over a domain with both depending on the same $\epsilon>0$. They show that $$\displaystyle\int_{D_\epsilon}f_\epsilon\,dx \to…
1
vote
1 answer

Pointwise convergence of a series $ \sum_{n=1}^\infty \frac{1}{\sqrt{n}}\left(e^{-\frac{x^2}{n}}-1 \right)) $

Consider the series for $x \in \mathbb{R}$ $$ \sum_{n=1}^\infty \frac{1}{\sqrt{n}}\left(e^{-\frac{x^2}{n}}-1 \right) $$ Then I have to prove that the series converges pointwise on $\mathbb{R}$. To prove this is all I need is to let $x \in…
Mathias
  • 917
1
vote
1 answer

Prove that a sequence of functions is pointwise convergent

I study pointwise convergence for sequences of functions. I am not sure If I do it right, so I would like to know If my way of solving it is the right way, and if it is not help me with a solution. Here is my problem:$f_n:[0,1] \rightarrow…
1
vote
1 answer

How to negate this statement

Let $\{f_n:A\to\mathbb{R}\}_{n\ge 1}$ is a sequence of functions that converges pointwise to some function $f:A\to\mathbb{R}$ and let $A_n:=\{x\in A:|f_n(x)-f(x)|\ge\alpha\}$ for some fixed constant $\alpha$ (Some other hypotheses on $f_n$ and $f$…
augustoperez
  • 3,216
1
vote
1 answer

Pointwise convergence of a sequence of piecewise functions {fn}

or any x∈[0,∞), there is always Nx∈ℕ s.t. Nx>x, thus we have fn(x)=e−x,∀n≥Nx, which means limn→∞fn(x)=e−x,∀x∈[0,∞) To show that the convergence is uniform, it suffices to show that limn→∞supx≥0|fn(x)−f(x)|=0 For any n∈ℕ, there are 3 cases If x≤n,…
7th Guy
  • 51
1
vote
1 answer

Typewriter sequence does not converge pointwise.

I am wondering why does the typewriter sequence defined here on example 4 does not converge pointwise? $f_n= \mathbb{1}_{\left [\frac{n-2^k}{2^k},\frac{n-2^k+1}{2^k}\right]}$ for $ k\geq0 $ and $2^k \leq n < 2^{k +1}$
abc
  • 71
1
vote
1 answer

Proving $n^\alpha x^n (1-x)$ converges pointwise formally

Let $f_n(x) = n^\alpha x^n(1-x)$ for any fixed $\alpha \in \mathbb{R}$ and $x \in [0,1]$. Prove $f_n$ converges to $0$ pointwise (via the definition). I considered that $|n^\alpha x^n(1-x) - 0| = n^\alpha x^n (1-x) \leq n^\alpha x^n$. But then I'm…
Natash1
  • 1,379
1
vote
1 answer

Pointwise convergence and uniformly convergence. Is this correct?

Let $F$ be a $C^1$ function defined in $\mathbb R$ and satisfies $F(0)>0$ and if $|x|>1$ then $F(x)=0$ Then, I think $g_n (x):=F(x-n)$ can converge pointwisely to $g(x)=0$ but don't think it can converge uniformly. Is this correct? Anyway I don't…
lacm
  • 501
0
votes
0 answers

prove there is no pointwise convergence of $\sin(nx)$

I was reading a calculus book and there was this task: prove that you cannot select a pointwise convergent subsequence from the sequence $$f_n(x) = \sin(nx)$$ consider that it's on $$[0, 1]$$ I've tried to prove it using definition of pointwise…
jiraffe
  • 165
0
votes
1 answer

Is this a pointwise convergent function?

For the series of functions $f_{k}(x)$ defined by $$f_{k}(x)=\begin{cases}k \quad 0
0
votes
1 answer

Proving formally that this set of functions converges pointwise

For $$f_n(x)= \left\{ \begin{array}{ll} n & x\geq n \\ 1 & x< n \\ \end{array} \right. $$ Graphically (is this usually how it's first approached), I can see that $f_n$ approaches to the function $f(x) = 1$ pointwise. This is my proof…
Natash1
  • 1,379
-2
votes
1 answer

Pointwise convergence of $\cos$ functions

I've been getting used to pointwise convergence but I have no Idea how to do harder examples. $$f(n)=\cos(z/n^5)/n!$$ How would I should that this converges pointwise to $f=0$ on $D(0,1)$. I'd really appreciate the help
Rich
  • 11